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Morgarella [4.7K]
1 year ago
10

The amount and the concentration of a salt solution is given. How much salt would you get if you evaporated all water from this

solution?
80g of a 35% solution

The amount and the concentration of a salt solution is given. How much salt would you get if you evaporated all water from this solution?

Im really desperate, I will make you brainliest if u answer both of them correctly
20g of a 17% solution
Mathematics
1 answer:
Gnoma [55]1 year ago
7 0

Answer:

  • 28 g
  • 3.4 g

Step-by-step explanation:

These problems only make sense if the percentage is by weight. To find the amount of salt, multiply the amount of solution by the percentage that is salt:

a) (80 g)(35%) = 28 g . . . . weight of salt

__

b) (20 g)(17%) = 3.4 g . . . . weight of salt

_____

<em>Comment on percent</em>

You know that % means /100, so 35% = 35/100 = 0.35.

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Jennifer has a bag of chips that contains 2 red chips and 1 black chips. If she also has a fair die, what is the probability tha
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4 0
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A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
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Answer:

The correct conclusion is:

<em>"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."</em>

Step-by-step explanation:

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The doctor measures the heights, in inches, of a sample of 40 male students from the baseball team.

Using this data, the doctor calculates the 95% confidence interval (63.5, 74.4).

The following conclusions is valid:

<em>"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."</em>

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For the given case, the confidence level is 95% and the corresponding confidence interval is (63.5, 74.4) which represents the true mean of heights for male students at the college where the doctor measured heights.

Therefore, it is valid to conclude that the doctor is 95% confident that the mean height of male students at the college is within the interval of (63.5, 74.4).

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