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ch4aika [34]
1 year ago
8

(b) Amira takes 9 hours 25 minutes to complete a long walk. (i) Show that the time of 9 hours 25 minutes can be written as 113 1

2 hours. ​
Mathematics
2 answers:
geniusboy [140]1 year ago
5 0

<em>Answer: x= mc2 Is the formula of the given question</em>

attashe74 [19]1 year ago
3 0

Answer:

average speed = 24 ÷ \frac{113}{12\\} = \frac{288}{113}

Step-by-step explanation:

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Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. He was
RUDIKE [14]

Answer:

Graph these two points: (0, 360), (30, 0)

Step-by-step explanation:

Since Amir drove for 30 minutes at a rate of 12 meters, that means that he started at an elevation of 360 feet. The easiest way to graph this, is to place one dot at (0, 360), and at (30, 0).

8 0
2 years ago
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Identify the explicit function for the sequence in the table.
juin [17]
14 - 9 = 5
19 - 14 = 5
24 - 19 = 5
29 - 24 = 5

It is an arithmetic sequence with differences, b = 5 and a = 9
a(n) = a + b(n - 1)
a(n) = 9 + 5(n - 1)

The answer is B
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2 years ago
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The variable complex number z is given by z=1+cos 2θ+isin2θ,where θ takes all values in the interval −1/2π&lt;θ&lt;1/2π
FinnZ [79.3K]
The given complex number is
 z = 1 + cos(2θ) + i sin(2θ), for -1/2π < θ < 1/2π

Part (i)
Let V = the modulus of z.
Then
V² = [1 + cos(2θ)]² + sin²(2θ)
     = 1 + 2 cos(2θ) + cos²2θ + sin²2θ

Because sin²x + cos²x = 1, therefore
V² = 2(1 + cos2θ)

Because cos(2x) = 2 cos²x - 1, therefore
V² = 2(1 + 2cos²θ - 1) = 4 cos²θ
Because  -1/2π < θ < 1/2π,
V = 2 cosθ                          PROVEN

Part ii.
1/z = 1/[1 + cos2θ + i sin 2θ]
\frac{1}{z} = \frac{(1+cos2\theta - i\, sin2\theta)}{(1 + cos 2\theta + i\, sin 2\theta)(1+cos2\theta - i \,sin2\theta)}\\ = \frac{1+cos2\theta - i \,sin 2\theta}{(1+cos2\theta)^{2} + sin^{2}2\theta}

The denominator is
(1+cos2\theta)^{2}+sin^{2}2\theta \\ = 1+2cos2\theta+cos^{2}2\theta+sin^{2}2\theta \\ =2cos2\theta+2 \\ = 2(1+cos2\theta)

Therefore
\frac{1}{z} = \frac{1}{2} -i \frac{sin2\theta}{2(1+cos2\theta)}

The real part of 1/ = 1/  (constant).
6 0
2 years ago
Which is the graph of the linear inequality 2x – 3y &lt; 12? On a coordinate plane, a solid straight line has a positive slope a
RoseWind [281]

Answer:

A dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the right of the line is shaded.

Step-by-step explanation:

To graph the solution set of the inequality 2x - 3y < 12, first plot the dashed line 2x - 3y = 12 (dashed because the inequality has sign < without notion "or equal to"). This line passes through the points (0,-4) and (3,-2) (their coordinates satisfy the equation of the line). this line has positive slope because

3y=2x-12\\ \\y=\dfrac{2}{3}x-4

and the slope of the line is 2/3.

Now, identify where the origin is (in the region or outside the region). Substitute (0,0) into the inequality:

2\cdot 0-3\cdot 0=0

This means coordinates of the origin satisfy the inequality, so origin belongs to the shaded region. Thus, shade that part which contains origin.

6 0
2 years ago
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Which of the following completes the proof?
mihalych1998 [28]

Answer:

c

Step-by-step explanation:

4 0
2 years ago
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