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1 year ago

8

(b) Amira takes 9 hours 25 minutes to complete a long walk. (i) Show that the time of 9 hours 25 minutes can be written as 113 1

2 hours.

2 answers:

geniusboy [140]1 year ago

5 0

<em>Answer: x= mc2 Is the formula of the given question</em>

attashe74 [19]1 year ago

3 0

Answer:

average speed = 24 ÷ $\frac{113}{12\\}$ = $\frac{288}{113}$

Step-by-step explanation:

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Determine the value of $a$. [asy] pair w=(0,4); pair x=(0,0); pair y=(4,0); pair z=y+7/sqrt(2)*(1,1); dot(w); dot(x); dot(y); do

grandymaker [24]

Answer:

a=7

Step-by-step explanation:

The image is rendered and attached below.

Triangle WXY is an Isosceles right triangle, since WX=XY.

First, we determine the length of WY using Pythagoras Theorem.

$WY=\sqrt{4^2+4^2}\\WY=\sqrt{32}$

Since triangle WXY is Isosceles, $\angle XYW=45^\circ$

$\angle XYZ=\angle XYW+\angle WYZ\\135^\circ=45^\circ+\angle WYZ\\\angle WYZ=135^\circ-45^\circ=90^\circ$

Therefore:

Triangle WYZ is a right triangle with WZ as the hypothenuse.

Applying Pythagoras Theorem

$WZ^2=WY^2+YZ^2\\9^2=(\sqrt{32})^2+a^2\\a^2=81-32\\a^2=49\\a^2=7^2\\$Therefore: a=7$

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2 years ago

The radar on a ship picks up two shipwrecks, A and B, 2.5 miles beneath the surface. The distance between the shipwrecks is 0.6

polet [3.4K]

We have
tan 12.5 = 60 / adj rearrange as
adj = 60 / tan 12.5 = about 270.64 m

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1 year ago

Billy Jo's school is selling tickets to a Fall Festival. On the first day of ticket sales the school sold 3 adult ticket and 8 s

denis23 [38]

Answer:

Y = 6

Step-by-step explanation:

On the first day of ticket sales the school <em><u>sold 3 </u></em>adult ticket and <em><u>8 student </u></em>tickets for a <em><u>total of $72</u></em>. The school took in <em><u>$152</u></em> on the second day by selling<em><u> 7 adult tickets and 16 student tickets.</u></em> How much is a student ticket?

Day 1: 3x + 7y = 72

Day 2: 7x + 16y = 152

This becomes a system of equations.

3x+8y=72

3x+8y+−8y=72+−8y (Add -8y to both sides)

3x=−8y+72

3x/3 = −(8y+72)/3

X = (-8/3) y + 24

Substitute (-8/3) y + 24 for x in7x+16y=152:

7(-8/3 y + 24) + 16y = 152

-8/3 y + 168 = 152 (Simplify both sides of the equation)

-8/3 y + 168 − 168 = 152 + (−168) (Add -168 to both sides)

-8/3 y = -16

(-8/3 y)/(-8/3 y) = -16/ -8/3 y (Divide both sides by (-8)/3)

<u><em>y = 6</em></u>

<em>If you wanted to keep going...</em>

Substitute 6f or y in x = (-8/3) y + 24

(-8/3) y + 24 = (-8/3) (6) + 24

SImplify: x = 8

<em>X = 8 and </em><u><em>Y = 6</em></u>

<u><em></em></u>

Hope this helps! <em>♥</em>

<u><em>~A.W.E.</em></u><em>S.W.A.N~</em>

6 0

2 years ago

Marcia has two credit cards and would like to consolidate the two balances into one balance on the card with the lower interest

lakkis [162]

Answer:

Option B ,$133.92 is correct

Step-by-step explanation:

By consolidating both balances in Card B,APR of 12% would apply to funds in card A as well

Let us approach the question by solving for monthly payment of Card A using 12% APR as follows while making use of excel pmt formula:

=pmt(rate,nper,-pv,fv)

rate is the monthly rate on the card which is 12%/12=1%

nper is the number of months of payment which is 12 months * 4 years=48

pv is the current balance in the card which is $1,389.47

fv is the total amount of monthly repayment which is taken as zero

=pmt(1%,48,-1389.47,0)=$ 36.59

Using 16% monthly payment is $39.38 which is given already

Total monthly payments for 16%=$39.38*48=$1890.24

Total monthly payments for 12% APR=$36.59*48=$1756.32

savings in total repayments=savings in interest=$1890.24 -$1756.32 =$133.92

4 0

1 year ago

Approximate the area under the curve y = x² from x = 2 to x = 5 using a Right Endpoint approximation with 6 subdivisions.

Tanzania [10]

Answer:

$\text{Area}\,=36.75$

Step-by-step explanation:

Using right estimation point simply means to form a bunch of rectangles between the two limits, x =2 and x = 5. and add the areas of all those rectangles.

There must be 6 subdivisions between 2 and 5. so, to do that:

$\Delta{x}=\dfrac{5-2}{6}=0.5$

the length of each subdivision is 0.5 units. That also means that the 6 rectangles in between the limits will each have the base length of 0.5 units.

So the endpoints of each subdivision from 3 to 5 will be:

$\begin{tabular}{|c|c|c|c|c|}3&3.5&4&4.5&5\\\end{tabular}$

By <em>right </em>endpoint approx<em>, </em>we mean that the height of the rectangles will be determined by the right endpoint of each subdivision, that is, it must be equal to the function value of the first limit.

$\begin{tabular}{|c|c|c|}subdivision&$x$&height($y=x^2$)&3 to 3.5&3.5&12.25&3.5 to 4&4&16&4 to 4.5&4.5&20.25&4.5 to 5&5&25\end$

Note that we have used the right-end-point of the subdivision to determine the height the rectangles.

All that's left to do now is to simply calculate the areas of the each of the rectangles. And add them up.

the base of each of the rectangle is $\Delta{x}=0.5$

and the height is determined in the table above.

$\text{Area}\,=(0.5\times12.25)+(0.5\times16)+(0.5\times20.25)+(0.5\times25)$

$\text{Area}\,=0.5(12.25+16+20.25+25)$

$\text{Area}\,=36.75$

3 0

2 years ago