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2 years ago

What is the surface area of the shaded front face of the composite solid?

Mathematics

2 answers:

Alexus [3.1K]2 years ago

6 0

$\begin{matrix}
((8*4)-(2*3))cm^2\\=(32-6)cm^2\\\mathbf{26\:cm^2}
\end{matrix}$

ANEK [815]2 years ago

3 0

Answer:

c. 26 square centimeters

Step-by-step explanation:

The given figure's area can be calculated by subtracting the area of the small cut out with dimension 2 cm by 3 cm from the complete area of the shaded portion with dimensions 8 cm by 4 cm.

So, area of the shaded portion is :

$(8\times4)-(2\times3)$

= $32-6$

= 26 cm square.

Therefore, option C is the answer.

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Find the sum of the first 63 terms of –19, -13, -7 …

boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : $S_n = \frac{n}{2}(2a + (n - 1)d)$

Given n = 63 and we found a = -19 and d = 6

$\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)$

$\implies S_6_3 = \frac{63}{2}(-38 + (62)6)$

$\implies S_6_3 = \frac{63}{2}(-38 + 372)$

$\implies S_6_3 = \frac{63}{2}(334)$

$\implies S_6_3 = {63}(167) = 10521$

The Sum of First 63 terms is 10521

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2 years ago

Lola bought x pencils that cost $0.25 each and y erasers that cost $0.50. She spent less than $3. Which graph represents Lola’s

ValentinkaMS [17]

I thing you forfot to ipload the graphs! I see no graphs to choose from, just the question itself! Please provide to graphs in order to help. Thanks

6 0

2 years ago

Read 2 more answers

Brody had his computer repaired at Store A. His bill was:

tekilochka [14]

Answer:

$190.80 gratuity tip.

Step-by-step explanation:

Adding up the initial cost and tax, it adds up to $1,272. Subtracting 85% from the total is $190.80.

7 0

2 years ago

1.An object falls from rest on a high tower and takes 5.0 s to hit the ground. Calculate the object’s position from the top of t

Arte-miy333 [17]

We will be using this equation for this problem
d = ut + ½.at²
Given:
initial velocity, u = 0 (falling from rest) 
acceleration, a = +9.80 m/s²(taking down as the convenient positive direction) 
Time = 1.0s, 2.0s, 3.0s, 4.0s, 5.0s 

Using .. d = ½.at² each time (each calculation is the distance from the top) 
For 1.0s .. d = ½ x 9.80 x (1²) = 4.90 m 
For 2.0s .. d = ½ x 9.80 x (2²) = 19.60 m 
3.0s .. d = 44.10m (you show the working for the rest) 
4.0s .. d = 78.40 m 
5.0s .. d = 122.50m 

Plot distance (displacement from the top) on the y-axis against time on the x-axis (label axes and give units for each).The line of best fit will be a smoothly upward curving line getting progressively steeper. Do not join graph points with straight lines.

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2 years ago

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Twenty-five juniors from a University volunteer to allow their Math GRE test scores to be used in a study. These 25 juniors had

fgiga [73]

Let's start first by writing down the given:
σ = 100
sample mean = 450
sample size = 25

These information, plus the fact that we know that the population is approximately normally distributed, would tell us that we can use the normal distribution curve in analyzing the problem.

A confidence interval of the mean is just a range statistically estimated to contain the population mean. For a 90% confidence interval, we would look at the Z-table and see where 90% of the data falls. We'll notice that it will fall within 1.645 standard deviations of the mean.

Next, we look for the standard error of the mean. This will have a formula
$error= \frac{standard deviation of population}{ \sqrt{N} }$

The standard error would just therefore be equal to
$\frac{100}{ \sqrt{25} }= \frac{100}{5} =20$

Lastly, we just get the product of the standard error and 1.645 and add it to 450 for the maximum value and subtract it to 450 for the minimum value.
$450-20(1.645)=417.1$
$450+20(1.645)=482.9$

ANSWER: 417.1<μ<482.9

8 0

2 years ago