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ziro4ka [17]
2 years ago
12

If a child accidentally swallowed 1.6 fluidounces of FEOSOL Elixir, containing 2/3 gr of ferrous sulfate per 5 mL, how many mill

igrams (to the nearest hundreth) of ferrous sulfate did the child ingest? (Hint: use the smaller available conversion factor] Your Answer: Answer units
Mathematics
1 answer:
GuDViN [60]2 years ago
8 0

Answer:

the amount of ferrous sulphate child will digest = 213.3 mg

Step-by-step explanation:

Given,

Amount of FEOSOL Elixir swallowed by child = 1.6 Fluid ounces

                                                                           = 1.6 x 29.57 ml

                                                                           = 47.312 ml

\textrm{Amount of ferrous sulphate contained in 5 ml of of solution}=\ \dfrac{2}{3}\ grams

\textrm{So, amount of ferrous sulphate contained in 1 ml of solution}\ =\ \dfrac{2}{3\times 5}

                                                                    =\ \dfrac{2}{15}

\textrm{So,the amount of ferrous sulphate contained in the 1.6 ml of FEROSOL}=1.6\times \dfrac{2}{15}

                  =\ \dfrac{3.2}{15}

                  = 0.2133 gram

                  = 213.3 mg

So, the amount of ferrous sulphate child will digest = 213.3 mg

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Write an exponential function in the form y<br> and (3,72).<br> ab" that goes through points (0,9)
Vikentia [17]

Answer:

y=9 ( {2}^{x} )

Step-by-step explanation:

Let the exponential function be

y = a {b}^{x}

We substitute (0,9) to get:

9 = a {b}^{0}

9 = a(1)

a = 9

The equation now becomes:

y = 9 {b}^{x}

We substitute (3,72) to get:

72 =9  {b}^{3}

8={b}^{3}  \\  {2}^{3}  =  {b}^{3}

b = 2

The equation is therefore

y=9 ( {2}^{x} )

3 0
2 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

7 0
2 years ago
Researchers from Dartmouth Medical School conducted a study in 2003 to look at the connection between watching actors smoking in
docker41 [41]

Answer:

The 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies is (0.37, 0.40).

Step-by-step explanation:

A confidence interval is an interval estimate of the population parameter. The confidence interval has a certain probability of consisting the true value of the parameter.

The (1 - <em>α</em>) % confidence interval for the population proportion (<em>p</em>) is given by:

CI=\hat p\pm z_{\alpha/2}\times \sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

n = 6522\\\hat p=0.38\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table for the critical value.

Construct the 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies as follows:

CI=\hat p\pm z_{\alpha/2}\times \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.38\pm 1.96\times \sqrt{\frac{0.38(1-0.38)}{6522}}\\=0.38\pm 0.0118\\=(0.3682, 0.3918)\\\approx (0.37, 0.40)

Thus, the 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies is (0.37, 0.40).

8 0
1 year ago
Franklin rides his bike to the beach averaging 18mph. He rides home along the same route. What speed must he average on the way
Sedaia [141]
  • <em>Answer:</em>

<em> 24 mph</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>Vm = 21mph</em>

<em>V1 = 18mph</em>

<em>V2 = ?</em>

<em>Vm = (V₁ + V₂)/2</em>

<em>2Vm = V₁ + V₂</em>

<em>V₂ = 2Vm - V₁</em>

<em>replace Vm ; V₁</em>

<em>V₂ = 2×21mph - 18mph</em>

<em>= 42mph - 18mph</em>

<em>= 24 mph</em>

<em>Good luck !</em>

8 0
2 years ago
hich uses the​ high-low method to analyze cost​ behavior, has determined that machine hours best predict the​ company's total ut
Crank

Answer:

1)- Variable utilities cost per machine hour = 1.6 per machine hour

2)- Fixed cost = 1740

3)-Total cost on 1220 Machine hour will be

= 3692

Step-by-step explanation:

1) CALCULATE VARIABLE UTILITIES COST PER MACHINE HOUR :

Variable utilities cost per machine hour = Change in cost/high machine hour-low machine hour

=4076-3388/1460-1030

Variable utilities cost per machine hour = 1.6 per machine hour

2) Fixed cost = Total cost-variable cost

= 3388-(1030*1.6)

Fixed cost = 1740

3) Total cost on 1220 Machine hour will be (1220*1.6+1740) = 3692

3 0
1 year ago
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