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2 years ago

A city determines that a planned community must have at least 4 acres of developed and open space, and the difference

Mathematics

1 answer:

FinnZ [79.3K]2 years ago

3 0

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x -----> the number of open acres

y ----> the number of developed acres

we know that

$x+y \geq 4$ -----> inequality A

$x\leq 1$ ----> inequality B

Remember that

if the number of open acres, x, can be no more than 1. then the number of open acres, x must be less than or equal to 1

Solve the system of equations by graphing

The solution is the shaded area (Note The number of acres cannot be a negative number)

The graph in the attached figure

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The population of a village is modeled by the function P(t) = 890e0.024t, where P is the population after t years. What does 890

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Answer:

I believe the answer is A. Population Growth Rate

Step-by-step explanation:

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2 years ago

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If X is a normal random variable with parameters µ = 10 and σ 2 = 36, compute

alex41 [277]

Answer:

Step-by-step explanation:

Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,

X is N(10, 6)

Or z = $\frac{x-10}{6}$

is N(0,1)

a) P(X > 5),

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(b) P(4 < X < 16),

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2 years ago

On a test, leo is asked to completely factor the polynomial 3x3 – 3x 5x2 – 5. he uses double grouping to get (x2 – 1)(3x 5). has

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No, Leo's answer is not a product of prime polynomials because x2 – 1 can be factored. This is a difference of squares. He should continue factoring to get

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2 years ago

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To solve -9 - 16m = 7, what steps would you use?

Ne4ueva [31]

First your going to add 9 to both sides.

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2 years ago

Colin invests £2350 into a savings account. The bank gives 4.2% compound interest for the first 4 years and 4.9% thereafter. How

mixer [17]

To solve this, we are going to use the compound interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ is the final amount after $t$ years
$P$ is the initial investment
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year

For the first 4 years we know that: $P=2350$ , $r= \frac{4.2}{100} =0.042$ , $t=4$ , and since the problem is not specifying how often the interest is communed, we are going to assume it is compounded annually; therefore, $n=1$ . Lest replace those values in our formula:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2350(1+ \frac{0.042}{1} )^{(1)(4)}$
$A=2350(1+0.042)^{4}$
$A=2770.38$

Now, for the next 6 years the intial investment will be the final amount from our previous step, so $P=2770.38$ . We also know that: $r= \frac{4.9}{100} =0.049$ , $t=6$ , and $n=1$ . Lets replace those values in our formula one more time:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2770.38(1+ \frac{0.049}{1})^{(1)(6)$
$A=2770.38(1+0.049)^6$
$A=3691.41$

We can conclude that Collin will have <span>£3691.41 in his account after 10 years.</span>

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2 years ago