answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
viva [34]
2 years ago
14

The graphs of the quadratic functions f(x) = 6 – 10x2 and g(x) = 8 – (x – 2)2 are provided below. Observe there are TWO lines si

multaneously tangent to both graphs.(a) The line simultaneously tangent to both graphs having the LARGEST slope has equation: (Two decimal places of accuracy.)y = ___ x + ___(b) The other line simultaneously tangent to both graphs has equation:(Two decimal places of accuracy.)y = ___ x + ___
Mathematics
1 answer:
natta225 [31]2 years ago
6 0

Answer:

a) y = 7.74*x + 7.5

b)  y = 1.148*x + 6.036

Step-by-step explanation:

Given:

                                  f(x) = 6 - 10*x^2

                                  g(x) = 8 - (x-2)^2

Find:

(a) The line simultaneously tangent to both graphs having the LARGEST slope has equation

(b) The other line simultaneously tangent to both graphs has equation,

Solution:

- Find the derivatives of the two functions given:

                                f'(x) = -20*x

                                g'(x) = -2*(x-2)

- Since, the derivative of both function depends on the x coordinate. We will choose a point x_o which is common for both the functions f(x) and g(x). Point: ( x_o , g(x_o)) Hence,

                                g'(x_o) = -2*(x_o -2)

- Now compute the gradient of a line tangent to both graphs at point (x_o , g(x_o) ) on g(x) graph and point ( x , f(x) ) on function f(x):

                                m = (g(x_o) - f(x)) / (x_o - x)

                                m = (8 - (x_o-2)^2 - 6 + 10*x^2) / (x_o - x)

                                m = (8 - (x_o^2 - 4*x_o + 4) - 6 + 10*x^2)/(x_o - x)

                                m = ( 8 - x_o^2 + 4*x_o -4 -6 +10*x^2) /(x_o - x)

                                m = ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x)

- Now the gradient of the line computed from a point on each graph m must be equal to the derivatives computed earlier for each function:

                                m = f'(x) = g'(x_o)

- We will develop the first expression:

                                m = f'(x)

                                ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

Eq 1.                          (-2 - x_o^2 + 4*x_o + 10*x^2) = -20*x*x_o + 20*x^2

And,

                              m = g'(x_o)

                              ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

                              -2 - x_o^2 + 4*x_o + 10*x^2 = -2(x_o - 2)(x_o - x)

Eq 2                       -2 - x_o^2 + 4*x_o+ 10*x^2 = -2(x_o^2 - x_o*(x + 2) + 2*x)

- Now subtract the two equations (Eq 1 - Eq 2):

                              -20*x*x_o + 20*x^2 + 2*x_o^2 - 2*x_o*(x + 2) + 4*x = 0

                              -22*x*x_o + 20*x^2 + 2*x_o^2 - 4*x_o + 4*x = 0

- Form factors:       20*x^2 - 20*x*x_o - 2*x*x_o + 2*x_o^2 - 4*x_o + 4*x = 0

                              20*x*(x - x_o) - 2*x_o*(x - x_o) + 4*(x - x_o) = 0

                               (x - x_o)(20*x - 2*x_o + 4) = 0  

                               x = x_o   ,     x_o = 10x + 2    

- For x_o = 10x + 2  ,

                               (g(10*x + 2) - f(x))/(10*x + 2 - x) = -20*x

                                (8 - 100*x^2 - 6 + 10*x^2)/(9*x + 2) = -20*x

                                (-90*x^2 + 2) = -180*x^2 - 40*x

                                90*x^2 + 40*x + 2 = 0  

- Solve the quadratic equation above:

                                 x = -0.0574, -0.387      

- Largest slope is at x = -0.387 where equation of line is:

                                  y - 4.502 = -20*(-0.387)*(x + 0.387)

                                  y = 7.74*x + 7.5          

- Other tangent line:

                                  y - 5.97 = 1.148*(x + 0.0574)

                                  y = 1.148*x + 6.036

You might be interested in
Let the function f(x) have the form f(x) = Acos(x-C). To produce a graph that
Gala2k [10]

Answer:

A has to be 2

Step-by-step explanation:

In the expression f(x)=A*cos(x-C), the multiplicative factor A represents what is called the "amplitude of the wave-shaped function that you obtain as the graph. Such amplitude is understood as half of the crest-to-through distance of the wavy curve.

From the drawing, the crest is at y=2 and the through at y=-2 (a distance of 4 units) therefore the value of A should be half of that distance: 4/2 = 2

6 0
2 years ago
Read 2 more answers
Help????????? If so....
Vinil7 [7]

Answer:

I think it equals 55

4 0
2 years ago
Read 2 more answers
the map below shows the location of 3 houses where you had to do lawn work today. Your truck gets 8 miles per gallon of gasoline
sergiy2304 [10]

Answer:

the answer is 3.80 cents

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The equation d = can be used to calculate the density, d, of an object with mass, m, and volume, V. Which is an equivalent equat
Kamila [148]
Since:
Density=Mass/Volume
Mass=Volume*Density
Therefore, Volume=Mass/Density
4 0
2 years ago
Read 2 more answers
In a group of 1500 people, 585 have blood type A, 165 have blood type B, 690 have blood type O, and 60 have blood type AB. What
deff fn [24]
When calculating probability you need to remember that probability is:
something that you are observing divided by total number of participants.
The number you get is relative value(has value between 0 and 1) and if you want to get it in percentage (more clearly) just multiply it with 100.

In this case we are observing blood type B persons. Number of them is 165.
Total number of persons is 1500. Therefore our calculation looks like this:

165/1500 = 0.11    or  the probability is 0.11*100=11%
6 0
2 years ago
Read 2 more answers
Other questions:
  • Find the area of the following shape. You must show all work to receive credit. Please help!
    5·1 answer
  • What is the pre-image of vertex A' if the image shown on the graph was created by a reflection across the y-axis?
    15·3 answers
  • Two race cars,car x an y,are at the starting point of a two km track at the same time.car x and car y make one lap every 60 s an
    14·1 answer
  • The volume of this rectangular prism is 108 cubic feet.
    10·2 answers
  • Kathy and Mark Smith believe investing in their retirement is critical. Kathy began investing 20% of each paycheck in a retireme
    8·1 answer
  • Xerxes, Murray, Norah, Stav, Zeke, Cam, and Georgia are invited to a dinner party. They arrive in a random order and all arrive
    14·1 answer
  • A linear function that represents the number of animals adopted from the shelter is compared to a different linear function that
    14·1 answer
  • A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil
    13·2 answers
  • The segments represent roads in a town, measured in miles.
    12·2 answers
  • A hockey player needs to shoot a puck 55 meters from his current location to his opponent's goal to score a goal. After the shot
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!