Answer:
Part A: From 0 to 2 seconds, the height of the water balloon increases from 60 to 75 feet, therefore the water balloon's height is increasing during the interval [0,2]
Part B: From 2 to 4 seconds, the height of the water balloon stays the same at 75 feet, therefore the water balloon's height is the same during the interval [2,4] From 10 to 12 seconds, the height of the water balloon stays the same at 0 feet, therefore the water balloon's height is the same during the interval [10,12] From 12 to 14 seconds, the height of the water balloon stays the same at 0 feet, therefore the water balloon's height is the same during the interval [12,14]
Part C: The interval, [4,6] of the domain is when the water ballon's height decreases the fastest. The interval [4,6] decreases by 35 feet. The two other intervals that decrease are [6,8] and [8,10] which both have the same slope. They decrease by 20 feet. Therefore, this helps us conclude that the interval [4,6] decreases the fastest because 35 feet is a more significant decrease than 20 feet.
Part D: I predict that the height of the water balloon at 16 seconds is 0 feet. This is because at 10-14 seconds, the water balloon's height is 0 feet. In read-world situations, if the water balloon is on the ground which is 0 feet, it stays on the ground due to gravity.
Step-by-step explanation:
I hope this helps! I also do not know if it is all correct but I did research and everything so hopefully it is correct! Good luck!
we are given
we can use average rate of change formula from t=a to t=b
Here, we are given from t=1 to t=4
so, we will get formula as
now, we can plug values
now, we can simplify it
the average rate of change in the number of acres cleared for farming between t = 1 and t = 4 is 10 acres/ month.............Answer
This is an isosceles right triangle (AB = BC & ∠ B=90° - Given)
Then the angles at the base are equal and ∠ CAB = ∠ ACB = 45°
Theorem: Segment DE, joining the midpoints of 2 sides is:
1st) parallel to the 3rd side and
2nd) equal to half the measurement of the 3rd side
So if the 3rd side (hypotenuse) = 9 units, DE = 9/2 = 4.5 units
Answer: <span>w = [ y + 1] / [a + 2]
Solution step by step:
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1) given <span>formula: y-aw=2w-1
2) transpose aw and - 1
2w + aw = y + 1
3) common factor w:
w (a + 2) = y + 1
4) divide both sides by (a + 2):
w = [ y + 1] / [a + 2]
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You could do this with fractions. I'll do decimals later.
d = 3/4 mile
t = 2/3 hour
r = ????
r = 3/4 // 2/3 Invert and multiply the denominator
r = 3/4 * 3/2 = 9/8 = 1 1/8
If your calculator handles fractions, you can use it to do this. If not you can change this to a decimal.
d = 3/4 = 0.75 miles
t = 2/3 hour = 0.666666666 hours.
r = ???
d = r*t
r = d/t
r = 0.75 / 0.66666667
r = 1.125 miles / hour
which gives you exactly the same answer 1.125 = 1 1/8
