12x50=600 so 60 left
15x50=750 so 60 left
so the administration fee is 60
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
Answer:
His 95% confidence interval is (0.065, 0.155).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

His 95% confidence interval is (0.065, 0.155).
His assistant would have to take 4 hour 30 minutes while Mr. Itol would take 1 hour 30 minutes.
Which grade is this and which school?