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Leno4ka [110]
2 years ago
12

Haruka hiked several kilometers in the morning. She hiked only 666 kilometers in the afternoon, which was 25\%25%25, percent les

s than she had hiked in the morning.
How many kilometers did Haruka hike in all?
Mathematics
2 answers:
skelet666 [1.2K]2 years ago
7 0

The answer is 14 km. I just did the quiz and 14 km was the right answer.

katen-ka-za [31]2 years ago
3 0

Answer:

She hiked 1,554 kilometers in all.

Step-by-step explanation:

Let the hiking kilometers for morning be x

Given that:

Hiking kilometers in afternoon = 666

According to given condition that afternoon kilometers are 25% less than morning:

x = 666 + 25% of x

By simplifying:

x = 666 + 0.25x

x - 0.25x = 666

0.75x = 666

Dividing both sides by 0.75 we get:

x = 666/0.75

x = 888 kilometers

She hiked 888 kilometers in morning

And

Total = 888 + 666 =1554 km

i hope it will help you!

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120 days

Step-by-step explanation:

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34, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144

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Prove that (sec 12A-1)/(sec 6A-1)=tan 12A/tan 3A
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Let x=3A. Recall the following identities,

\cos^2\theta=\dfrac{1+\cos2\theta}2

\sin^2\theta=\dfrac{1-\cos2\theta}2

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Now,

\dfrac{\sec12A-1}{\sec6A-1}=\dfrac{\sec4x-1}{\sec2x-1}

=\dfrac{\cos2x(1-\cos4x)}{\cos4x(1-\cos2x)}

=\dfrac{2\cos2x\sin^22x}{\cos4x(1-\cos2x)}

=\dfrac{2\cos2x\sin^22x(1+\cos2x)}{\cos4x(1-\cos^22x)}=\dfrac{2\cos2x\sin^22x(1+\cos2x)}{\cos4x\sin^22x}=\dfrac{2\cos2x(1+\cos2x)}{\cos4x}

=\dfrac{4\cos2x\cos^2x}{\cos4x}

=\dfrac{4\cos2x\cos^2x\sin4x}{\cos4x\sin4x}=\dfrac{4\cos2x\cos^2x\tan4x}{\sin4x}

=\dfrac{4\cos2x\cos^2x\tan4x}{2\sin2x\cos2x}=\dfrac{2\cos^2x\tan4x}{\sin2x}

=\dfrac{2\cos^2x\tan4x}{2\sin x\cos x}=\dfrac{\cos x\tan4x}{\sin x}

=\dfrac{\tan4x}{\frac{\sin x}{\cos x}}=\dfrac{\tan4x}{\tan x}=\dfrac{\tan12A}{\tan3A}

QED

5 0
2 years ago
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