The are of a rectangle is calculated by multiplying the length and the width of the shape. First, we determine the dimensions of this figure. We do as follows:
Width = 12 - 2x - 2x = 12 - 4x
Length = 12 - x - x = 12 - 2x
Area = (Length)(Width)
Area = (12 - 2x )(12-2x)
we have

Step 
<u>Clear the variable y</u>

Adds
both sides


Step 
<u>Convert in function notation</u>
Let


therefore
<u>the answer is</u>

Answer:
a). x = 11
b). m∠DMC = 39°
c). m∠MAD = 66°
d). m∠ADM = 36°
e). m∠ADC = 18°
Step-by-step explanation:
a). In the figure attached,
m∠AMC = 3x + 6
and m∠DMC = 6x - 49
Since "in-center" of a triangle is a points where the bisectors of internal angles meet.
Therefore, MC is the angle bisector of angle AMD.
and m∠AMC ≅ m∠DMC
3x + 6 = 8x - 49
8x - 3x = 49 + 6
5x = 55
x = 11
b). m∠DMC = 8x - 49
= (8 × 11) - 49
= 88 - 49
= 39°
c). m∠MAD = 2(m∠DAC)
= 2(30)°
= 60°
d). Since, m∠AMD + m∠ADM + m∠MAD = 180°
2(39)° + m∠ADM + 66° = 180°
78° + m∠ADM + 66° = 180°
m∠ADM = 180° - 144°
= 36°
e). m∠ADC = 
= 
= 18°
18+4=27\qo/89 so that answer must me 18+4=27\qo but carry the y
AB is divided into 8 equal parts and point C is 1 part FROM A TO B, so the ratio is 1:7, with C being 1/7 of the way. The ratio is k, found by writing the numerator of the ratio (1) over the sum of the numerator and denominator (1+7). So our k value is 1/8. Now we need to find the rise and the run (slope) of the points A and B.

. That gives us a rise of -4 and a run of 12. The coordinates of C are found in this formula:
![C(x,y)=[ x_{1} +k(run), y_{1} +k(rise)]](https://tex.z-dn.net/?f=C%28x%2Cy%29%3D%5B%20x_%7B1%7D%20%2Bk%28run%29%2C%20y_%7B1%7D%20%2Bk%28rise%29%5D)
. Filling in accordingly, we have
![C(x,y)=[-3+ \frac{1}{8}(12),9+ \frac{1}{8}(-4)]](https://tex.z-dn.net/?f=C%28x%2Cy%29%3D%5B-3%2B%20%5Cfrac%7B1%7D%7B8%7D%2812%29%2C9%2B%20%5Cfrac%7B1%7D%7B8%7D%28-4%29%5D%20%20)
which simplifies a bit to

. Finding common denominators and doing the math gives us that the coordinates of point C are

. There you go!