I = prt
p = 7430
r = 5%....turn to decimal = 0.05
t = 3
I = (7430)(0.05)(3)
I = 1114.50 <===
Answer:
The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches
Step-by-step explanation:
We have that:

Let the dimension of the paper be x and y;
Such that:


So:

Substitute 128 for Area

Make x the subject

When 1 inch margin is at top and bottom
The length becomes:


When 2 inch margin is at both sides
The width becomes:


The New Area (A) is then calculated as:

Substitute
for x

Open Brackets

Collect Like Terms



To calculate the smallest possible value of y, we have to apply calculus.
Different A with respect to y

Set

This gives:

Collect Like Terms

Multiply through by 


Divide through by 2

Take square roots of both sides



Recall that:



Recall that the new dimensions are:


So:




To double-check;
Differentiate A'




The above value is:

This means that the calculated values are at minimum.
<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>
Explanation:
Quadrants 2 and 3 houses points that have negative x-values, while as Quadrants 1 and 4 houses points that have positive x-values.
If 'your sister' completes the text with negative y-value, the point would be in Q3.
If 'your sister' completes the text with positive y-value, the point would be in Q2.
Answer:
C.
Step-by-step explanation:
We are given that an expression

We have to find the simplified form of given expression.
We know that

Using the property then we get

Hence, the simplified form of
is given by

Option C is true.
It is given in the question that,
Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.
And

Since QS bisects angle PQR, therefore

Substituting the values, we will get
