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Oliga [24]
2 years ago
12

Given the figure below is a special type of trapezoid and WX || YZ, which angle pairs can be proven supplementary by the given i

nformation? Select all that apply.
∠W and ∠Z
∠W and ∠Y
∠X and ∠Y
∠X and ∠Z
∠W and ∠X

Mathematics
2 answers:
RSB [31]2 years ago
8 0

Answer:

The answer:

<W and <Z

<X and <Y

<W and <X


Step-by-step explanation:


svetlana [45]2 years ago
6 0

Answer:  The correct options are

(A) ∠W and ∠Z

(C) ∠X and ∠Y.

Step-by-step explanation:  Given that the figure is a special type of trapezoid and WX || YZ.

We are to select all the angle pairs that can be proven supplementary by the given information.

We know that

if two parallel lines are cut by a transversal, then the sum of the measures of interior angles on the same side of the transversal is 180°.

In the given trapezoid, we have

WX || YZ and WZ is a transversal, so ∠W and ∠Z are interior angles on the same side of the transversal WZ.

So,

m∠W + m∠Z = 180°.

This implies that ∠W and ∠Z are supplementary.

Similarly,

WX || YZ and XY is a transversal, so ∠X and ∠Y are interior angles on the same side of the transversal XY.

So,

m∠X + m∠Y = 180°.

This implies that ∠X and ∠Y are supplementary.

Therefore, the pairs of angles that can be proven supplementary with the given information are

∠W and ∠Z ;   ∠X and ∠Y.

Thus, (A) and (C) are correct options.

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In a random sample of 8 people with advanced degrees in biology, the mean monthly income was $4744 and the standard deviation wa
eimsori [14]

Answer: u= ( 4342.08, 5145.92).

Step-by-step explanation: the population mean is estimated using the sample by the formulae assuming a 95% confidence level

u = x' + Zα/2 * (√σ/n) or x' - Zα/2 * (√σ/n)

u = estimated population mean

x' = sample mean = 4744

n = sample size =8

σ = sample standard deviation. = 580

α = level of significance = 1- confidence level = 1-0.95= 0.05

Zα/2 = z score from the normal distribution table for a 2 tailed test = 1.96

First boundary value for interval

u = 4744 + 1.96 ( 580/√8)

u = 4744 + 1.96 * (205.0609)

u = 4744 + 401.92

u = 5145.92

Second boundary value for interval

u = 4744 - 1.96 ( 580/√8)

u = 4744 - 1.96 * (205.0609)

u = 4744 - 401.92

u = 4342.08

Thus the confidence interval for population mean is

u= ( 4342.08, 5145.92).

3 0
2 years ago
Rona mixes 2 pounds of meat with some chopped vegetables to make a mixture. She divides the mixture into 4 equal portions. Each
AVprozaik [17]

Answer:

First choice: (1/4)(2 + v) = 3; v = 10 pounds of chopped vegetables

Step-by-step explanation:

"2 pounds of meat with some chopped vegetables"

2 + v

"She divides the mixture into 4 equal portions."

(1/4)(2 + v)

"Each portion weighs 3 pounds."

(1/4)(2 + v) = 3

2 + v = 12

v = 10

Answer: (1/4)(2 + v) = 3; v = 10 pounds of chopped vegetables

7 0
2 years ago
Prove the following using a proof by contradiction:The average of four real numbers is greater than or equal to at least one of
skelet666 [1.2K]

Answer:

By contradiction it can be proved that:

Average of four real numbers will be greater than or equal to at least one of the four real numbers.

Step-by-step explanation:

Method of contradiction means we assume opposite to the facts to be proved and then we contradict our assumption.

As a result, we prove the fact.

Here, let the four number be:

p, q, r, s

The average will be Sum of all numbers divided by count of numbers.

\dfrac{p+ q+ r+ s}4

Now, let us assume the opposite that the average is less than all the numbers.

i.e.

\dfrac{p+ q+ r+ s}4

\dfrac{p+ q+ r+ s}4

Now, let us add all of them:

\dfrac{p+ q+ r+ s}4 +\dfrac{p+ q+ r+ s}4 +\dfrac{p+ q+ r+ s}4 +\dfrac{p+ q+ r+ s}4  < p+q+r+s\\\Rightarrow \dfrac{4(p+q+r+s)}4

Which can never be possible hence, our assumption is contradicted.

our assumption is wrong.

Therefore, by contradiction it is proved that:

Average of four real numbers will be greater than or equal to at least one of the four real numbers.

8 0
2 years ago
We went to the market to buy some fruit. We decided to buy some apples, strawberries, and oranges. If we buy 2 apples, 3 boxes o
Ksivusya [100]

Step-by-step explanation:

Let the amount of apples bought be x

Amount of strawberries bought be y and;

amount of oranges bought be z

If we buy 2 apples, 3 boxes of strawberry, and 4 oranges, the fruit would cost $15.30, then this will be expressed as;

2x+3y+4z = 15.30 ........... 1

If we buy 1 box of strawberry, 4 apples, and 2 oranges, the fruit would cost $10.90, this will be expressed as:

4x+y+2z = 10.90 ......... 2

If we buy 1 orange, 5 apples and 2 boxes of strawberry, the fruit would cost $13.70, this is expressed as:

5x+2y+x = 13.70 .......... 3

Solving the three equations simultaneously:

2x+3y+4z = 15.30 ........... 1

4x+y+2z = 10.90 ......... 2

5x+2y+z = 13.70 .......... 3

Reduce the number of equations

multiply equation 1 by 2 and subtract from equation 2

equation 1 * 2 will give:

4x+6y+8z = 30.6 ........... 4

eqn (4)-eqn(2)

6y-y + 8z-2z = 30.6-10.90

5y+6z = 19.7 ......... 5

Also multiply equation 2 by 5 and eqn 5 by 4 and subtract from each other.

eqn(2)* 5 will give:

20x+5y+10z = 54.5 .......... *

eqn(3) * 4 will give

20x+8y+4z = 54.8.......**

Subtsrct ** from *

8y-3y+(4z-10z)= 54.8-54.5

5y-6z = 0.3 .................. 6

Equate 5 and 6 and solve:

5y+6z = 19.7 ......... 5

5y-6z = 0.3 .................. 6

subtract:

6z+6z = 19.7+0.3

12z = 20

z = 20/12

z = 1.67

Substitute z = 1.67 into eqn 6

5y-6(1.67) = 0.3

5y - 10 = 0.3

5y = 10.3

y = 10.3/5

y = 2.06

Substitute z = 1.67 and y = 2.06 into equation 1

From 1:

2x+3y+4z = 15.30

2x+3(2.06)+4(1.67) = 15.30

2x+6.18+6.68 = 15.30

2x+12.86 = 15.30

2x = 15.30-12.86

2x = 2.44

x = 2.44/2

x = 1.22

<em>Therefore 1 apple costs $1.22, 1 strawberry costs $2.06 and 1 orange costs $1.67</em>

3 0
2 years ago
G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =
Svetach [21]
Presumably you should be doing this using calculus methods, namely computing the surface integral along \mathbf r(u,v).

But since \mathbf r(u,v) describes a sphere, we can simply recall that the surface area of a sphere of radius a is 4\pi a^2.

In calculus terms, we would first find an expression for the surface element, which is given by

\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k
\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j
\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k
\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u

So the area of the surface is

\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u
=-2\pi a^2(\cos\pi-\cos 0)
=-2\pi a^2(-1-1)
=4\pi a^2

as expected.
6 0
2 years ago
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