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Oliga [24]
1 year ago
12

Given the figure below is a special type of trapezoid and WX || YZ, which angle pairs can be proven supplementary by the given i

nformation? Select all that apply.
∠W and ∠Z
∠W and ∠Y
∠X and ∠Y
∠X and ∠Z
∠W and ∠X

Mathematics
2 answers:
RSB [31]1 year ago
8 0

Answer:

The answer:

<W and <Z

<X and <Y

<W and <X


Step-by-step explanation:


svetlana [45]1 year ago
6 0

Answer:  The correct options are

(A) ∠W and ∠Z

(C) ∠X and ∠Y.

Step-by-step explanation:  Given that the figure is a special type of trapezoid and WX || YZ.

We are to select all the angle pairs that can be proven supplementary by the given information.

We know that

if two parallel lines are cut by a transversal, then the sum of the measures of interior angles on the same side of the transversal is 180°.

In the given trapezoid, we have

WX || YZ and WZ is a transversal, so ∠W and ∠Z are interior angles on the same side of the transversal WZ.

So,

m∠W + m∠Z = 180°.

This implies that ∠W and ∠Z are supplementary.

Similarly,

WX || YZ and XY is a transversal, so ∠X and ∠Y are interior angles on the same side of the transversal XY.

So,

m∠X + m∠Y = 180°.

This implies that ∠X and ∠Y are supplementary.

Therefore, the pairs of angles that can be proven supplementary with the given information are

∠W and ∠Z ;   ∠X and ∠Y.

Thus, (A) and (C) are correct options.

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The number that is 75% of one less than a number n.
gizmo_the_mogwai [7]

Answer:

The number is n-0.75

Step-by-step explanation:

Here in this question, we are interested in giving a number which is 75% of 1 less than a number n.

The first thing we do here is to calculate the value of 75% of 1.

That would be;

75/100 * 1 = 0.75

So this value less than n will be;

n- 0.75

7 0
1 year ago
What is the definition of undefined term?
maxonik [38]
I think the answer is :

In Geometry, we have several undefined terms<span>: point, line and plane. From these three </span>undefined terms<span>, all other </span>terms<span> in Geometry can be </span>defined. ... The first term<span> is point. The second </span>term<span> is plane. And the third </span>undefined term<span> is the line.
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Hope This Helps.
5 0
1 year ago
Read 2 more answers
Which recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1?
Trava [24]

f (n + 1) = f(n) – 5  is the recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1

<h3><u>Solution:</u></h3>

Given that,

f(1) = 6 and n ≥ 1

Given sequence is 6, 1, -4, -9, -14

<em><u>Let us first analyse the logic used in this sequence</u></em>

6 - 5 = 1

1 - 5 = -4

-4 - 5 = -9

-9 - 5 = -14

Thus the next terms in sequence are obtained by subtracting 5 from previous term

Thus a recursive formula can be formed as:

f (n + 1) = f(n) – 5

Where "n" is the nth term

Let us check our recursive formula:

f(1+ 1) = f(1) - 5

f(2) = f(1) - 5

f(2) = 6 - 5 = 1

Thus we have got f(2) = 1 which is correct as per given sequence

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2 years ago
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In the first option, there is likely to be a correlation but it cannot be a linear one as goals are missed even from inside the keeper's box.

In the second option, it is safe to assume that each person will at least 2 other so this will follow an exponential model.

In the third option, the stopping distance is given by the equation of motion:
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4 0
1 year ago
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Coordinates, gradient and tangent work (see image).
Ivenika [448]

Answer:

a) P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)

b) 4x+2h

c) 4x

Step-by-step explanation:

Given the curve

y=2x^2-5

a) If the x-coordinate of P is x, then the y-coordinate is 2x^2-5, so point P has coordinates (x,2x^2-5)

If the x-coordinate of Q is x+h, then the y-coordinate is 2(x+h)^2-5 so point Q has coordinates (x+h,2(x+h)^2-5)

b) The gradient of the secant RQ is

\dfrac{y_Q-y_P}{x_Q-x_P}\\ \\=\dfrac{(2(x+h)^2-5)-(2x^2-5)}{(x+h)-x}\\ \\=\dfrac{2(x+h)^2-5-x^2+5}{x+h-x}\\ \\=\dfrac{2(x+h)^2-2x^2}{h}\\ \\=\dfrac{2x^2+4xh+2h^2-2x^2}{h}\\ \\=\dfrac{4xh+2h^2}{h}\\ \\=4x+2h

c) If h\rightarrow 0, then the gradient 4x+2h\rightarrow 4x

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