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Ira Lisetskai [31]
2 years ago
6

Please help. I am getting in trouble so please try to be correct...

Mathematics
1 answer:
vichka [17]2 years ago
7 0

Answer: The answer is A 17in2

Step-by-step explanation:

In the question it states that the triangles are congruent (both the same).

  first I found the area of the top orange triangle.

the formula to find the area of a triangle is \frac{1}{2} bh (base times Height).

so I did  \frac{1}{2} 3.23* 5.12  which gave me 8.27.

Since the triangles are congruent (the same) they would both have the same area along with base and height. so I multiplied 8.27 by 2 (because there are two triangles) and got 16.54 which rounds up to 17.

the question also stated to find the APPROXIMATE area (close to the actual, but not completely accurate or exact.)

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Sarah is planning to spend a week at her friend's summer house in Miami Beach. All meals will be provided by her friend's parent
Rus_ich [418]

Answer:

500$

Step-by-step explanation:

5 0
2 years ago
Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k.
yan [13]

Answer:

The value of k is 3.

Step-by-step explanation:

The function f(x) passes through the points (0,4) and (-6,-2)

So the equation of the function is \frac{y-4}{4-(-2)} = \frac{x-0}{0-(-6)}

⇒ y = x + 4 ....... (1)

Again the function g(x) passes through the points (0,4) and (-2,-2).

Therefore, the equation of g(x) will be  \frac{y-4}{4-(-2)} =\frac{x-0}{0-(-2)}

⇒ y = 3x + 4

Therefore, g(x) = 3x + 4 = f(3x) {from equation (1).

So, the value of k is 3. (Answer)

3 0
2 years ago
Read 2 more answers
The combined average weight of an okapi and a llama is 450450450 kilograms. The average weight of 333 llamas is 190190190 kilogr
Kisachek [45]
I'm going to assume that you meant 450kg for the combined weight, 190kg more and 3 Llamas. I'm pretty sure Llamas and Okapis don't weigh 450450450kg (that's 993,073,252 pounds). :)

x= Okapi weight
y= Llama weight

EQUATIONS:
There are 2 equations to be written:

1) 450kg is equal to the weight of one Okapi and one Llama

450kg= x + y

2) The weight of 3 llamas is equal to the weight of one Okapi plus 190kg.

3y=190kg + x


STEP 1:
Solve for one variable in one equation and substitute the answer in the other equation.

450kg= x + y
Subtract y from both sides
450-y =x


STEP 2:
Substitute (450-y) in second equation in place of x to solve for y.

3y=190kg + x
3y=190 + (450-y)
3y=640 -y
add y to both sides

4y=640
divide both sides by 4

y=160kg Llama weight


STEP 3:
Substitute 160kg in either equation to solve for x.

3y=190kg + x
3(160)=190 + x
480=190 + x
Subtract both sides by 190

290= x
x= 290kg Okapi weight


CHECK:
3y=190kg + x
3(160)=190 + 290
480=480

Hope this helps! :)
8 0
2 years ago
A population has a standard deviation of 80. A random sample of 400 items from this population is selected. The sample mean is d
Helga [31]

Answer:

ME= 1.8808 * \frac{80}{\sqrt{400}} =7.5232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =80 represent the population standard deviation

n=400 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.8808

The margin of error is given by:

ME= 1.8808 * \frac{80}{\sqrt{400}} =7.5232

4 0
2 years ago
Makayla has $8 to buy tickets at the school fair. Each ticket costs @1.5. Which inequality best represents how many tickets she
cricket20 [7]

Answer:

n\le 5

Step-by-step explanation:

Let n be the number of tickets Makaya has to buy.

If the cost of one ticket is $1.5, then the cost of n tickets is $1.5n.

Makayla has $8 to buy tickets at the school fair, thus

1.5n\le 8\\ \\n\le \dfrac{8}{1.5}\\ \\n\le \dfrac{80}{15}\\ \\n\le \dfrac{16}{3}\\ \\n\le 5\dfrac{2}{3}

The maximum number of tickets Makaya can buy is 5, so

n\le 5

5 0
2 years ago
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