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algol13
1 year ago
11

A battery factory typically produces 12,000 batteries per day and uses 50 boxes for packing the batteries. If the number of boxe

s needed for packing is proportional to the number of batteries produced, how many more boxes would be needed on a day when 18,000 batteries are produced?
Mathematics
1 answer:
weqwewe [10]1 year ago
4 0

Answer:

25 more boxes is needed

Step-by-step explanation:

12000 batteries require 50 boxes. Let's find the unit rate.

That is, how many batteries are in each box??

That's 12,000/50!

12,000/50 = 240 batteries per box

Now, to find how many boxes we would need for 18,000 batteries, we will have to divide the total (18000) by 240(number of batteries per box). That is:

18,000/240 = 75 boxes

We would need 75 boxes to pack 18,000 batteries.

We want "how many MORE boxes needed", so we will the excess:

75 - 50 = 25 more boxes is needed

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What are the domain and range of f (x) = (one-fifth) Superscript x?
natka813 [3]

Answer:

The domain of the function is all real numbers (-\infty,\infty) and the range is all positive real numbers (0,\infty)

Step-by-step explanation:

We have the following function f(x)=(\frac{1}{5} )^x and we want to find the domain and the range.

The function we have is an example of an exponential function f(x)=b^x with b > 0 and b ≠ 1. This types of functions in general have the following properties:

  • It is always greater than 0, and never crosses the x-axis
  • Its domain is the set of real numbers
  • Its Range is the Positive Real Numbers (0,\infty)

The domain of a function is the specific set of values that the independent variable in a function can take on.

When determining domain it is more convenient to determine where the function would not exist.

This function has no undefined points nor domain constraints. Therefore the domain is (-\infty,\infty).

The range is the resulting values that the dependent variable can have as x varies throughout the domain. Therefore the range is (0,\infty).

We can check our results with the graph of the function.

7 0
2 years ago
Read 2 more answers
the trinomial x2 bx c factors to (x m)(x n). if b is negative and c is positive, what must be true about m and n?
galina1969 [7]

For c to be positive, and for b to be negative, m must be negative and n must be negative.


X^2 - bx + c = (x - m)(x - n).

c is the product of m and n. If both m and n are positive, c would be positive. However b is the sum of m and n, therefore to make b negative, both m and n must be negative to ensure that the product of m and n is positive


7 0
2 years ago
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Business services ordered a chair that cost $220.59. Upon arrival they received an invoice for $261.47. If the California sales
sladkih [1.3K]

Answer:

Cost of shipping and handling = $23.453

Step-by-step explanation:

Given

Price of Chair=$220.59

Tax=7.9%

Invoice Price=$261.47

In order to find the cost of shipping and handling, we have to subtract the cost of chair and the tax from the invoice price of chair.

To find the tax,

Tax amount=220.59*0.079

=$17.42661

Now,

Cost of shipping and handling=$261.47-$220.59-$17.42661

=$23.453 ..

6 0
1 year ago
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Suppose 50 percent of the customers at Pizza Palooza order a square pizza, 70 percent order a soft drink, and 35 percent order b
Firdavs [7]

Answer:

Ordering a soft drink is independent of ordering a square pizza.

Step-by-step explanation:

20% more customers order a soft drink than pizza, therefore they cannot be intertwined.

Given: P(A)=0.5 & P(B)=.7

P(A∩B) =  P(A) × P(B)

=  0.5 × .7

=  0.35

P(A∪B) =  P(A) + P(B) - P(A∩B)

=  0.5 + .7 - 0.35

=  0.85

P(AΔB) =  P(A) + P(B) - 2P(A∩B)

=  0.5 + .7 - 2×0.35

=  0.5

P(A') =  1 - P(A)

=  1 - 0.5

=  0.5

P(B') =  1 - P(B)

=  1 - .7

=  0.3

P((A∪B)') =  1 - P(A∪B)

=  1 - 0.85

=  0.15

7 0
1 year ago
On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are given  that

f(x)=6(\frac{1}{3})^x

Function f decreases from quadrant  2 to quadrant 1 and approaches  y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

g(-1)=6\times (\frac{1}{3})=2

Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
1 year ago
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