<span>1)Given: AB = 4 AD = 6
What is the name of the radius of the larger circle?
the answer part 1) is
the radius </span>of the larger circle is AD
<span>2)Given: AB = 4 AD = 6
What point is in the interior of both circles?
the answer Part 2) is
The point A (the center of the circles)
</span><span>3) Given: AB = 4 AD = 6
Which points are in the exterior of both circles?</span><span>
the answer Part 3) is
</span><span>E and G
</span><span>4)The circles are _____.
</span><span>the answer Part 4) is
</span><span>concentric
</span>
<span>5)If AC = 20 and BD = 8, what is the radius of the smaller circle?
</span>we know that
radius smaller circle=AB
and
AB=AC-BD--------> AC=20-12-------> AC=8 units
the answer part 5) is
the radius of the smaller circle is 12 units
<span>6)Given: AB = 4 AD= 6
What is the length of BD?</span>
we know that
AD=AB+BD
solve for BD
BD=AD-AB--------> BD=6-4-----> BD=2 units
the answer Part 6) is
the length of BD is 2
<span>7)Given: AB = 4 AD = 6
What is the name of the radius of the smaller circle?</span>
the answer Part 7) is
the name of the radius of the smaller circle is AB
I am not sure about this but here goes nothing: d=2.5t+2.2 is very familiar to y=mx+b y=d m=2.5 x=t b=2.2 to find a new quasion we substitute d and t into place wich equals 1=2.5(0)+b simplification and you get b=1 so your answer is d=2.5t+1
<h2>
Plane's speed without wind i s 117.68 mph</h2>
Step-by-step explanation:
We have speed of plane without wind is x.
Distance to brothers place = 200 miles.
A headwind of 20 mph slowed down the plane's speed on the first leg of the trip
Speed to brothers place = x - 20
We have
Distance = Speed x Time

A tailwind of 20 mph sped up the plane on the return trip
Speed of return trip = x + 20
We have
Distance = Speed x Time

The entire trip took 3.5 hours.
That is

Plane's speed without wind i s 117.68 mph
Answer:

Step-by-step explanation:



