The domain of the graph is everything x is allowed to equal. Parentheses are used to show that x can be everything up to, but not including that number. Brackets are used to show x can be anything up to, and including, that number. The comma between the two numbers indicates that x can be anything between those two numbers.
Here, the time goes on the x axis and the distance will go on the y axis.
Time: 0 1 2 3 4 5 6 7 8 9 10
<span>Distance: 0.0 5.5 12.0 20.0 28.5 36.0 44.0 56.5 64.0 75.0
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Since we are dealing with the domain, we really only need to focus on the time.
Time: 0 1 2 3 4 5 6 7 8 9 10
From this, we see that the values go from 0 to 10. This means that x can be anything from 0 to 10. Because there are y values that correlate with the numbers 0 and 10, we know that the domain will include 0 and 10. This indicates we must use brackets.
Knowing all of this information, we can now write our domain as:
[0, 10]
Do you know how to calculate the first derivative?
If so, what is h'(x)...
Once you have h'(x) substitute 0 for x into this equation<span />
Answer:
8 hours
Step-by-step explanation:
Job v starts at time 0 and completes at time 3.
Job w starts at time 1 and completes at time 4.
Job x starts at time 4 and completes at time 8.
Job y starts at time 8 and completes at time 10.
Job z starts at time 10 and completes at time 15.
The average completion time is (3 +4 +8 +10 +15)/5 = 8 . . . hours.
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<em>Comment on the schedule</em>
Jobs v and x are the only ones completed by the time due. The latest is 8 hours late. If they are scheduled in order of due time, jobs v, w, and y can be completed by the due time; the others will be 4 and 6 hours late.
Answer:
Remember that:
Speed = distance/time.
Then we can calculate the average speed in any segment,
Let's make a model where the average speed at t = t0 can be calculated as:
AS(t0) = (y(b) - y(a))/(b - a)
Where b is the next value of t0, and a is the previous value of t0. This is because t0 is the middle point in this segment.
Then:
if t0 = 100s
AS(100s) = (400ft - 0ft)/(200s - 0s) = 2ft/s
if t0 = 200s
AS(200s) = (1360ft - 50ft)/(300s - 100s) = 6.55 ft/s
if t0 = 300s
AS(300s) = (3200ft - 400ft)/(400s - 200s) = 14ft/s
if t0 = 400s
AS(400s) = (6250s - 1360s)/(500s - 300s) = 24.45 ft/s
So for the given options, t = 400s is the one where the velocity seems to be the biggest.
And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.
Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.
Answer:
Hey there!
We can't compare two measurements without converting them to the same units. Thus, we use proportions to make all the values into the same unit.
, which converts to centimetres to millimetres.
12.5 cm=125 mm.
Now, we can compare the values of 125 mm and 140 mm.
Clearly, we see that 140 mm is greater than 125 mm.
Let me know if this helps :)
