Answer:
m∠FJH=60°
Step-by-step explanation:
The complete question is
JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°
What is FJH
we know that
m∠FJH=m∠FJG+m∠GJH -----> equation A
If ray JG is an angle bisector of ∠FJH
then
m∠FJG=m∠GJH -----> equation B
substitute the given values in equation B and solve for x
(2x + 4)°=(3x -9)°
3x-2x=4+9
x=13
Find the measure of angle FJH
m∠FJH=(2x + 4)°+(3x -9)°
substitute the value of x
m∠FJH=(2(13) + 4)°+(3(13) -9)°
m∠FJH=(30)°+(30)°
m∠FJH=60°
Answer:
102,100 decigrams
Step-by-step explanation:
(564 dag + 458 dag) = 1021 dag
1021 dag × 100 dg/dag = 102100 dg
The two cases together weigh 102,100 decigrams.
_____
1 dag = 10 g
1 dg = 0.1 g
Answer:
(4x - 11i)(4x -+11i)
Step-by-step explanation:
Factor as a difference of squares
a² - b² = (a - b)(a + b)
note that i² = - 1
Given
16x² + 121
= (4x)² - (11i)²
= (4x - 11i)(4x + 11i)
Answer:
yes, it is possible to have the sum of square roots equal the square root of the sum of the radicands.
If either a or b equals zero, then the sums would be the same.
Since the square root of 0 is 0, adding it to a given radical would not change the radical. Also adding zero to the radicand would not change its value.
these are the right answer for E2020
A = P(1+(r/n))^nt
A = 500(1+(.09/1))^1<span>∗4
A = 500(1.09)^4
A = 705.79</span>
