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forsale [732]
2 years ago
15

In a triangle, suppose we know that side b=3 feet, side c=2 feet, and that angle A=140o. According to the Law of Cosines, the le

ngth of side a is approximately?
Mathematics
1 answer:
Oxana [17]2 years ago
7 0

Answer:

The length of third side of triangle is 4.195 feet.

Step-by-step explanation:

In a triangle as shown in the figure the law of cosines states that

a^{2}=c^{2}+b^{2}-2bccos(A)

Since it is given that

b = 3 feet

c = 2 feet

A = 140^{o}

Using these values in the above equation we get

a^{2}=2^{2}+3^{2}-2\times 3\times 2cos(140)\\\\\therefore a^{2}=17.596\\\\a=4.195feet

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\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
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-----------------------------\\\\

\begin{cases}
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b=10\\
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\\\\\\
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