Use different conversion factor to accomplish the task given above,
a. (78.9x10^-13 g) x (1 x 10^12 picogram/ 1 gram) = 7.89 pg
b. (6.41x10^-10 L) x (1 x 10^9 nanoliter / 1 L) = 0.641 nL
c. (3.15x10^11 m) x ( 1 x 10^-12 terameter / 1 meter) = Tm
d. (80 x10^-19) x (1 x10^18 atto / 1) = 8 atto
Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
600,000
Because 629,999 is closer to 600,000 than 700,000.
One way to describe the U.S. dollar if the foreign exchange rate between the U.S dollar and British pound changed from 1:1 to 1:07 is the dollar has weakened. The correct answer is C.
Answer:
7x - 5
Step-by-step explanation:
Let
Nina = x coins
Clayton = 6x - 5 coins
Expression for the total number of coins Nina and Clayton have altogether.
Nina + Clayton
= x + (6x - 5)
= x + 6x - 5
= 7x - 5
The correct answer and expression is 7x - 5
