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Tpy6a [65]
2 years ago
15

Ashley invests $9,720 in a one-month money market account paying 3.16% simple annual interest and $8,140 in a two-year CD yieldi

ng 3.23% simple annual interest. Assuming Ashley does not reinvest or renew these investments, how much money will she have when both investments reach maturity, to the nearest dollar?

Mathematics
2 answers:
tester [92]2 years ago
5 0
For the first investment. A = P(1 + rt); where p = 9,720, r = 0.0316 and t = 1/12
A = 9720(1 + 0.0316/12) = 9720(1.0026) = $9,746

For the second investment,
A = 8140(1 + 0.0323 x 2) = 8140(1.0646) = $8,666

Total amount she had = $9,746 + $8,666 = $18,412
Elodia [21]2 years ago
3 0

Answer:

D. $18,411

Step-by-step explanation:

I just answered it correct

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Benito and Tyler are painting opposite sides of the same fence. Tyler has already painted 19 ½ feet of his side of the fence whe
rewona [7]

Answer:

Part A: The time it will take for both of them to painted equal number of feet is 4.875 minutes

The number of feet Benito will have painted when the two sides have equal length is 73.125 feet

Part B: It is not true that Tyler will finish painting his side of the fence before Benito finishes painting his

Part C: Time to rest is 1.864 minutes

Step-by-step explanation:

The given information are;

The length of fence Tyler already painted when Benito started = 19 ¹/₂ feet

Benito paints 15 feet/minute

Tyler paints 11 feet/minute

Length of fence = 150 feet

Part A:

The time it will take for both of them to painted equal number of feet is given as follows;

11×t + 19.5 = 15×t

4×t = 19.5

t = 19.5/4= 4.875 minutes

The time it will take for both of them to painted equal number of feet = 4.875 minutes

The length Benito will have painted when the two sides have equal length = 15 × 4.875 = 73.125 feet

Part B: The time it will take Tyler to finish painting his side of the fence is given as follows;

11 × t + 19.5 = 150

t = (150 - 19.5)/11 ≈ 11.864 minutes

While the time it will take Benito to finish painting his side of the fence is given as follows;

15 × t  = 150

t = 150/15 ≈ 10 minutes

Therefore it is not true that Tyler will finish painting his side of the fence before Benito finishes painting his

Part C: Given that Benito finishes before Tyler, the length of time Benito gets to rest is given as follows;

Time to rest = Time Tyler takes to finish - Time Benito takes to finish

Time to rest = 11.864 - 10 = 1.864 minutes.

5 0
2 years ago
What does collinear mean
storchak [24]
Lying in the same straight line i think..

5 0
1 year ago
Read 2 more answers
If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that (x-1) is one of the factor of the given equation.

Remainder theorem can be applied as below:

\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  =\frac{(x-1)(x+3)(x+1)}{(x-1)}

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

5 0
2 years ago
Read 2 more answers
Wang Hao wants to spend at most $15 on dairy products. Each liter of goat milk costs $2.40 and each liter of cow's milk costs $1
Mashutka [201]

Answer:

2.40g + 1.20c ≤15

Step-by-step explanation:

Each liter of goat milk costs $2.40 and each liter of cow's milk costs $1.20

Let g = liters of goats milk

c = liters of cows milk

What we are buying is the liters times the cost

2.40g + 1.20c

This must be less than or equal to 15 dollars

2.40g + 1.20c ≤15

8 0
2 years ago
Read 2 more answers
I need help with finding the equation for #20 and # 22 for my brother we get the answer but it’s hard for us to write out how to
Pavel [41]

Answer:

Im not sure about 20 but 22 is 48

Step-by-step explanation:

4×96 =384

384÷8 = 48 orange per classroom

8 0
2 years ago
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