Answer:
Option d.
Step-by-step explanation:
we know that
The graph of a continuous probability distribution is a curve. Probability is represented by area under the curve.
The curve is called the probability density function (abbreviated as pdf).
We use the symbol f(x) to represent the curve
therefore
The probability density function f(x) represents . the height of the function at x.
5 19 6 -18
-3
-15 -12 18
5 4 -6 0
Therefore, the width is 5x^2 + 4x - 6
Hat grade are u? I'm just asking cause the formulas are going with grade I could help if u want me too
Customer awareness is the same as customer responsibility. this is because a customer should always be aware of any deals, defectives, or flaws in the product. being “aware” means “having knowledge of a situation”. being aware of your purchases affects your responsibility and attentiveness. customers should always examine the closely before purchasing.
<span>Given:
75% of the five-star football recruits in the nation go to universities in the three most competitive athletic conferences. </span>→ 25% goes to other schools.
<span>
five-star recruits get full football scholarships 93% of the time, regardless of which conference they go to. </span>→ 7% of the 5-star recruits don't get full football scholarships.<span>
a. The probability that a randomly selected five-star recruit who chooses one of the best three conferences will be offered a full football scholarship?
75% * 93% = 69.75%
b. What are the odds a randomly selected five-star recruit will not select a university from one of the three best conferences?
25% of selected five-star recruit will not select a university from one of the three best conferences. I got the number based on the given data. Since, 75% will go, the remaining percent won't go. Total percentage should be 100% of the population.
c. Explain whether these are independent or dependent events. Are they Inclusive or exclusive?
These are independent events. One can still go to different school and still be legible for the full football scholarship.
For question 2, pls. see attachment.</span>