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2 years ago

For an Ap T1 =2 Tn =41 Sn = 860 then find n

Mathematics

1 answer:

KatRina [158]2 years ago

4 0

To find:-

Solution:-

Sn =860

T1 = 2

Tn = 41 , Tn = [a +( n-1 )d ]

n =?

SN = n/2 (2a + {n-1}d ) = 860

n/2( 2× 2+ (n-1)d ) = 860

n/2 (tn+t1) = 860

n/2 (41 +2) = 860

n/2 (43) = 860

n = (860 ×2 )/43

n = 40

Hope it helps you!!

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For an Ap T1 =2 Tn =41 Sn = 860 then find n​

For an Ap T1 =2 Tn =41 Sn = 860 then find n