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Which is a stretch of an exponential growth function? f(x) = Two-thirds (two-thirds) Superscript x f(x) = Three-halves (two-thir

ds) Superscript x f(x) = Three-halves (three-halves) Superscript x f(x) = Two-thirds (three-halves) Superscript x

2 answers:

Zepler [3.9K]2 years ago

9 0

Answer:f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Since, a function in the form of f(x) = ab^x

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

Growth function : If b > 1,

Decay function : if 0 < b < 1,

Since, In

f(x) =\frac{2}{3}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

in f(x) =\frac{2}{3}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

Step-by-step explanation:

Arte-miy333 [17]2 years ago

5 0

Answer:

f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Step-by-step explanation:

Since, a function in the form of $f(x) = ab^x$

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

Growth function : If b > 1,

Decay function : if 0 < b < 1,

Since, In

$f(x) =\frac{2}{3}(\frac{2}{3})^x$

$\frac{2}{3} < 1$

Thus, it is a decay function.

in $f(x) =\frac{3}{2}(\frac{2}{3})^x$

$\frac{2}{3} < 1$

Thus, it is a decay function.

in $f(x) =\frac{3}{2}(\frac{3}{2})^x$

$\frac{3}{2} > 1$

Thus, it is a growth function.

in $f(x) =\frac{2}{3}(\frac{3}{2})^x$

$\frac{3}{2} > 1$

Thus, it is a growth function.

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The first step is calculate the degrees of freedom, on this case:

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