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PIT_PIT [208]
2 years ago
13

Which is a stretch of an exponential growth function? f(x) = Two-thirds (two-thirds) Superscript x f(x) = Three-halves (two-thir

ds) Superscript x f(x) = Three-halves (three-halves) Superscript x f(x) = Two-thirds (three-halves) Superscript x
Mathematics
2 answers:
Zepler [3.9K]2 years ago
9 0

Answer:f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Since, a function in the form of f(x) = ab^x

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

Growth function : If b > 1,

Decay function : if 0 < b < 1,

Since, In

f(x) =\frac{2}{3}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

in f(x) =\frac{2}{3}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

Step-by-step explanation:

Arte-miy333 [17]2 years ago
5 0

Answer:

f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Step-by-step explanation:

Since, a function in the form of f(x) = ab^x

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

  • Growth function : If b > 1,
  • Decay function : if 0 < b < 1,

Since, In

f(x) =\frac{2}{3}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

in f(x) =\frac{2}{3}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

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aniked [119]

Answer:

The sample of sizes 2 and their mean are given below.

Step-by-step explanation:

The population consist of  5 values, S = {1, 3, 4, 4, 6}.

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Th formula to compute the mean is:

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(1, 3)                    \bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 6)                    \bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 6)                   \bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5

(4, 4)                   \bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

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