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PIT_PIT [208]
2 years ago
13

Which is a stretch of an exponential growth function? f(x) = Two-thirds (two-thirds) Superscript x f(x) = Three-halves (two-thir

ds) Superscript x f(x) = Three-halves (three-halves) Superscript x f(x) = Two-thirds (three-halves) Superscript x
Mathematics
2 answers:
Zepler [3.9K]2 years ago
9 0

Answer:f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Since, a function in the form of f(x) = ab^x

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

Growth function : If b > 1,

Decay function : if 0 < b < 1,

Since, In

f(x) =\frac{2}{3}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

in f(x) =\frac{2}{3}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

Step-by-step explanation:

Arte-miy333 [17]2 years ago
5 0

Answer:

f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Step-by-step explanation:

Since, a function in the form of f(x) = ab^x

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

  • Growth function : If b > 1,
  • Decay function : if 0 < b < 1,

Since, In

f(x) =\frac{2}{3}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{2}{3})^x

\frac{2}{3} < 1

Thus, it is a decay function.

in f(x) =\frac{3}{2}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

in f(x) =\frac{2}{3}(\frac{3}{2})^x

\frac{3}{2} > 1

Thus, it is a growth function.

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Triangle G F E is cut by line segment H J. Line segment H J goes from side G E to F E. The length of G F is 4 x minus 4, the len
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Answer:

HJ = 8  JE = 4

Step-by-step explanation:

it is given that H is the midpoint of GE and J is the midpoint of FE. According to the midpoint theorem the line segment connecting the midpoint of two sides is parallel to the three side and its length is half of the third side. since JH is connecting the midpoints.

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Now you just fill into your equations:

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1 year ago
Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
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Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

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2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

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Option (3) is true.

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In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations wil
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The center for Simulation A and Simulation B will be roughly equal.

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