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Ymorist [56]
2 years ago
8

A line passes through the point (0, -1) and has a positive slope. Which of these points could that line pass through?

Mathematics
3 answers:
aliina [53]2 years ago
8 2

Answer:

  (12, 3), (-2, -5), (1, 15)

Step-by-step explanation:

The line can pass through any point with a positive x-value and a y-value greater than -1. Those points include ...

  (12, 3), (1, 15)

The line can pass through any point with a negative x-value and a y-value less than -1. That point is ...

  (-2, -5)

__

In the attached, the green lines have positive slope; the red lines do not.

Guest
1 year ago
wrong
Mashutka [201]2 years ago
8 2

Answer:

(1,15) (12,3) (-2,-5)

Step-by-step explanation:

I answered this with desmos but it got deleted for some reason.

(-3,1) and (5,-2) have a negative slope when it passes through (0,-1)

(12,3), (1,15) and (-2,-5) have a positive slope when it passes through (0,-1)

Hope this helps:)

Guest1 year ago
1 0

All of those answers are wrong!

The real answer is (–3, 1) (5, –2)

Have a good day!

Guest
1 year ago
Yeah thxs omg your is awnser is soo right *__*
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12 is reallly 2 * 2 * 3

8 is really 2 * 2 * 2

now, the 2 * 2, is repeated in the factoring, so we use it once only.  We still have to account for the extra 2 and 3.

therefore, the LCD will be 2 * 2 * 2 * 3, or 24.

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Answer:

The result of applying the square root property of equality to this equation is x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}.

Step-by-step explanation:

Consider the provided equation.

\left(x+\dfrac{b}{2a}\right)^2=\dfrac{-4ac+b^2}{4a^2}

As the above equation is formed by perfect square trinomial so simply applying the square root property as shown:

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Isolate the variable x.

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