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Margaret [11]
1 year ago
9

Marcel is nearing graduation. He just met with his counselor and she showed him this information.

Mathematics
2 answers:
Troyanec [42]1 year ago
5 0

<u>Answer:</u>

The correct answer option is A. $4,400.

<u>Step-by-step explanation:</u>

Cost of the tuition and fees for 1 year = $12,500

Grants and scholarships for 1 year = $6500

Cost of room and board for 1 year = $8200

Cost for work study for 1 year = $9800

So basically, Marcel pays = (tuition and fees + cost of room and board)

                                          = $12,500 + $8,200 = $20,700

He can pay through the (grants and scholarships + cost for work-study) =  $6,500 + $9,800 = $16,300

Therefore, Marcel needs to borrow = $20,700 - $16,300 = $4,400

MrRa [10]1 year ago
4 0

Answer:

The answer is A

Step-by-step explanation:

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A mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt. Th
Arturiano [62]

Answer:

The probability of hitting the bullseye at least once in 6 attempts is 0.469.

Step-by-step explanation:

It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.

The probability of hitting bullseye in each attempt, p = 0.10

The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90

Let x be the event of  hitting the bullseye.

We need to find the probability of hitting the bullseye at least once in 6 attempts.

P(x\geq 1)=1-P(x=0)       .... (1)

According to binomial expression

P(x=r)=^nC_rp^rq^{n-r}

where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.

The probability that the dart thrower not hits the bullseye in 6 attempts is

P(x=0)=^6C_0(0.10)^0(0.90)^{6-0}

P(x=0)=0.531441

Substitute the value of P(x=0) in (1).

P(x\geq 1)=1-0.531441

P(x\geq 1)=0.468559

P(x\geq 1)\approx 0.469

Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.

3 0
1 year ago
HELP PLEASE !!!!!!!!!!!!
olganol [36]
30 dozen carnations.
20 dozen roses.
This means she spends 550, but makes 640. 
I hope this is right?
8 0
1 year ago
Simon has a quarter, dime, nickel, and penny in his pocket. He wants to buy a snack at the canteen that costs 40¢. If he pulls o
ludmilkaskok [199]

Answer:

It would be a 3/4 chance that he will pull the right 4 coins.

Step-by-step explanation:

8 0
1 year ago
There are 450 students in my high school. 39 students are taking AP
Lelechka [254]

Answer:

Chessebuger

Step-by-step explanation:

see the chesse burger is real good

7 0
1 year ago
Ivan and Adeline are in a classroom with a chalkboard. They are standing on different halves of the board, and on each half, the
solong [7]

Answer:

The number of times Ivan and Adeline have the same number written on the board is 6.

Step-by-step explanation:

Consider the procedure as follows:

  • On each half of the board, the number 2 is written.
  • On Ivan's teacher's signal, Ivan multiplies the number on his side of the board by -2 and writes the answer on the board, erasing the number he started with.
  • Adeline does the same on each signal, except that she multiplies by 2.
  • The teacher gives 10 signals in total.

Consider the numbers on each half of the board:

          Ivan                            Adeline

             2                                     2

      2 × -2 = -4                        2 × 2 = 4

     -4 × -2 = 8                         4 × 2 = 8

      8 × -2 = -16                      8 × 2 = 16

   -16 × -2 = 32                      16 × 2 = 32

   32 × -2 = -64                    32 × 2 = 64

  -64 × -2 = 128                   64 × 2 = 128

  128 × -2 = -256               128 × 2 = 256

-256 × -2 = 512                256 × 2 = 512

  512 × -2 = -1024              512 × 2 = 1024

-1024 × -2 = 2048           1024 × 2 = 2048

Thus, the number of times Ivan and Adeline have the same number written on the board is 6.

6 0
2 years ago
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