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1 year ago

8

For today only I authorize you to offer a free insurance plan for one year to go to Mission signer for service dangerously in re

gular clothes 6.99 a month what would you say the customer a year

1 answer:

alukav5142 [94]1 year ago

7 0

Answer:

1920

Step-by-step explanation:

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Julius earns $47,800 a year working for a delivery service. He is single and pays $2,152.60 in state income

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2 years ago

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A bacteria culture begins with 13 bacteria which triple in amount at the end of every hour. How many bacteria are grown during t

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The end of first hour = 13*3 = 39

The end of second hour = 39*3 = 117

The end of third hour = 117*3 = 351

The end of fourth hour = 351*3 = 1,053

The end of fourth hour = 1053*3 = 3,159

The end of fifth hour = 3159*3 = 9,477

The end of sixth hour = 9477*3 = 28,431

The end of seventh hour = 28341*3 = 85,293

The end of eighth hour = 85293*3 = 255,879

The end of ninth hour = 255879*3 = 767,637

The end of tenth hour = 767637*3 = 2,302,911

The correct answer is D.2,302,911

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2 years ago

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The number of species n found on islands typically increases with the area of the island A. Suppose that this relationship is su

Crazy boy [7]

Answer:

$n(A) = n_1A^k$

Step-by-step explanation:

Taking into account that the growth rate of the number of species on the island is proportional to the density of species (number of species between area of the island), a model based on a differential equation is proposed:

$\frac{dn}{dA} = k\frac{n}{A}$

This differential equation can be solved by the method of separable variables like this:

$\frac{dn}{n} = k\frac{dA}{A}$ with what you get:

$\int\ {\frac{dn}{n}}\ = k\int\ {\frac{dA}{A}}$

$ln|n| = kln|A|+C$ . Taking exponentials on both sides of the equation:

$e^{ln|n|} = e^{ln|A|^{k}+C}$

$n(A) = e^{C}A^{k}$

how do you have to $n (1) = n_1$ , then

$n(A) = n_1A^k$

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2 years ago

Write the ratio as a fraction in simplest form: 2.35 to 5.25.

Sliva [168]

Step-by-step explanation:

$\frac{2.35}{5.25} = \frac{235}{525} = \frac{47}{105} = 47 \: : \: 105 \\$

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2 years ago

WILL GIVE BRAINLIEST ANSWER!!

Natasha2012 [34]

Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

$\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}
\\\\\\
\boxed{b=\cfrac{200}{tan(16.38^o)}-a}
\\\\\\
tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\
-------------------------------\\\\
\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}$

make sure your calculator is in Degree mode.

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2 years ago

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