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aniked [119]
2 years ago
5

Below are the data collected from two random samples of 500 American students on the number of hours they spend in school per da

y (rounded to the nearest hour):
Number of hours in school per day
4
5
6
7
8
Sample A: Number of students
70
100
125
135
70
Sample B: Number of students
80
90
120
125
85


Meg concludes that students spend a mean of 7 hours in school each day. Tara thinks the mean is 6 hours. Who is correct—Meg or Tara? Explain your answer in two or three sentences. Make sure to use facts to support your answer
asap
Mathematics
1 answer:
lukranit [14]2 years ago
5 0
To find the mean you must add up all the numbers you have together and then divide the buy the amount of numbers you added. When you add these numbers up you get 30, and we have 5 numbers here, when we divide 30 by 5 we get 6. So, Tara is correct in saying that the mean is 6.
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Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
lianna [129]
<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

   Let the complex numbers be a+ib\textrm{ and }c+id.

Given, sum is 10i, difference is -4 and product is -29.

(a+c)+i(b+d)=10i ⇒ a+c=0,b+d=10

(a-c)+i(b-d)=-4 ⇒ a-c=-4,b-d=0

a=-2,c=2,b=5,d=5

(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

Hence, all three equations are consistent yielding the complex numbers -2+5i\textrm{ and }2+5i.

8 0
2 years ago
In 2001, a total of 15,555 homicide deaths occurred among males and 4,753 homicide deaths occurred among females. The estimated
deff fn [24]

Answer:

a. 11

b. 3

c. homicide mortality rate

d. 11:3

Step-by-step explanation:

a.) If 15,555 homicide cases were recorded among males of 139,813,000 population, then in every 100,000 males, the number of homicides cases will become:

= [15,555/139,813,000] * 100,000

= 11.13 aproximately 11 homicide cases in every 100,000 males.

b.) If 4,753 homicide cases were recorded among Females of 144,984,000 population, then in every 100,000 Females, the number of homicides cases will become:

= [4753/144,984,000] * 100,000

= 3.28 approximately 3 homicide cases in every 100,000 females

C.) Homicide-mortality rate

d.) ratio of male to female homicide rate = 11 : 3

e.) What those rates means is that in every 100,000

Males in 2001, 11 of them were Victims of homicide and in every 100,000 females, 3 of them are victims of homicide.

6 0
2 years ago
A caterer charges a $65 equipment fee to set up for a party and $9.50 per p person for food served at the party. Which of the fu
AleksAgata [21]

Answer:

The total cost function of having a party catered  is f(p)  =  65 + 9.50 p

Step-by-step explanation:

The equipment fee of the caterer = $65

The charge per plate = $9.50

Let, Total number of people invited in the party = p

So, the cost of plates of p people  = Number of people x Per plate cost

                                                         =  p  x $9.50

Now, Total Catering Cost = Equipment Fee +  Cost of all plates

or,                       Total cost =  $65  + p  x $9.50

Hence, the total cost function of having a party catered

 is f(p)  =  65 + 9.50 p.

3 0
2 years ago
Joanna pays $40 plus a $2 surcharge each month for her high-speed Internet service. Which table BEST represents the relationship
Musya8 [376]

can you show the tables ?

7 0
2 years ago
From a survey of coworkers you find that 32​% of 150 have already received this​ year's flu vaccine. An approximate 98​% confide
Artyom0805 [142]

Answer:

a) Narrower

b) Narrower

c) Wider            

Step-by-step explanation:

We are given the following in the question:

Proportion of coworker who received flu vaccine = 32​%

98​% confidence interval: (0.231​, 0.409​)

Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

​a) Sample size had been 600 instead of 150​

If we increase the sample size, thus the standard error of the interval decreases.

Since the standard error decreases, the confidence interval become narrower.

b) Confidence level had been 90​% instead of 98​%

As the confidence level increases, the confidence interval becomes narrower. This is due to a smaller value of z-statistic at 90% confidence level.​

c) Confidence level had been 99​% instead of 98​%

As the confidence level increases, the width of the confidence interval increases and the confidence interval become wider. This is because of a larger value of z-statistic at 99% confidence interval.

4 0
2 years ago
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