C=A-B, according to the information, the vector A⃗ has a magnitude of 3.00 and is directed parallel to
the negative y-axis: that means Vector OA (0, -3)
<span> and vector B</span>⃗<span> has a magnitude of 3.00 and is directed parallel to
the positive y-axis. </span>
that means Vector OB (0, 3), so C=A – B means vectOC = vect OA - vect
OB =(0,-3)-(0,3)=(0,-6), so the magnitude of OA is sqrt((-6)^2)=6, so C=6
and
according to the information (as measured counterclockwise from the positive
x-axis), so the answer is <span>C = 6.00; θ = 90˚</span>
