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2 years ago

DUPLICATE WITH ATTACHMENT

1 answer:

4 0

C=A-B, according to the information, the vector A⃗ has a magnitude of 3.00 and is directed parallel to the negative y-axis: that means Vector OA (0, -3)

and vector B⃗ has a magnitude of 3.00 and is directed parallel to the positive y-axis.

that means Vector OB (0, 3), so C=A – B means vectOC = vect OA - vect OB =(0,-3)-(0,3)=(0,-6), so the magnitude of OA is sqrt((-6)^2)=6, so C=6

and according to the information (as measured counterclockwise from the positive x-axis), so the answer is C = 6.00; θ = 90˚

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Gabe and Eugenia bought a house! Their loan is for $117,000 , for 15 years at an annual interest rate of 4% . This results in a

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Answer:

Principal element is $475.43

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Step-by-step explanation:

The amount of interest paid in month one is 4%*$117,000*1/12=$390

The interest is calculated based on the annual interest rate of 4% apportioned to reflect one month interest by multiplying by 1/12

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2 years ago

What is the angle θ that the field e⃗ makes with the surface of the slab, which is perpendicular to the x direction? express you

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Multiplying StartFraction 3 Over StartRoot 17 EndRoot minus StartRoot 2 EndRoot EndFraction by which fraction will produce an eq

ziro4ka [17]

The fraction which produce an equivalent fraction with a rational denominator is $\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

Explanation:

The equation is $\frac{3}{\sqrt{17}-\sqrt{2}}$

To find the rational denominator, let us take conjugate of the denominator and multiply the conjugate with both numerator and denominator.

Rewriting the equation, we have,

$\frac{3}{\sqrt{17}-\sqrt{2}}\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

Multiplying, we get,

$\frac{3(\sqrt{17}+\sqrt{2})}{(\sqrt{17})^{2}-(\sqrt{2})^{2}}$

Simplifying the denominator, we get,

$\frac{3(\sqrt{17}+\sqrt{2})}{17-2}$

Subtracting, the values of denominator,

$\frac{3(\sqrt{17}+\sqrt{2})}{15}$

Dividing the numerator and denominator,

$\frac{\sqrt{17}+\sqrt{2}}{5}$

Hence, the denominator has become a rational denominator.

Thus, the fraction which produce an equivalent fraction with a rational denominator is $\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

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