I just got this question. I think the answer is 5.
Answer:
= 391/11
Let say number = N
a certain number is increased by 5
= N + 5
,one-half of the result
= (N + 5)/2
Three -fifths of the excess of 61 over the number.
= (3/5)(61 - N)
Equating both
(N + 5)/2 = (3/5)(61 - N)
multiplying by 10 both sides
=> 5(N + 5) = 6(61 - N)
=> 5N + 25 = 366 - 6N
=> 11N = 391
=> N = 391/11
Step-by-step explanation:
