893 hundreds x 85 tens =
2 answers:
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An equation in the form 
is the line
that goes through the origins and whose tangent equates
. In general, any equation in the form 
is the equation of a line.
that goes through the origins and whose tangent equates
is the equation of a line.
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
<em>Question 1) </em>
The graph of is attached to the answer.
The graph of such a functio lies in first and third quandrant such that the graph tends to 0 when x→∞ or when x→-∞ and graph tends to ∞ when x→0.
We can also show the values of this equation on a table:
<u> x-values</u> <u> y-values</u>
1/2 4
1 2
2 1
3 2/3
<em>Question 2)</em>
The graph of the equation is attached to the answer.
we will get a upward parabola with this equation whose vetex is: (-1,-4).
The ordered pair on the graph could be shown with the help of a table:
<u>x-values</u> <u> y-values</u>
-1 -4
0 -3
-3 0
1 0
