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Anna71 [15]
2 years ago
15

John Anderson bought a home with a 10.5% adjustable rate mortgage for 30 years. He paid $9.99 monthly per thousand on his origin

al loan. At the end of 5 years, he owes the bank $55,000. Now that interest rates have gone up to 12.5%, the bank will renew the mortgage at this rate or John can pay $55,000. John decides to renew and will now pay $10.68 monthly per thousand on his loan. (You can ignore the small amount of principal that has been paid.) What is the amount of the old monthly payment? What is the amount of the new monthly payment? What is the percent of increase in his new monthly payment?
Mathematics
2 answers:
kogti [31]2 years ago
8 0

Answer:

The original mortgage required a payment equal to $9.99 per every $1,000, so the total monthly payment = $9.99 x ($55,000 / $1,000) = $9.99 x 55 = $549.45

The new mortgage requires a payment equal to $10.68 per every $1,000, so the total monthly payment = $10.68 x ($55,000 / $1,000) = $10.68 x 55 = $587.40

The percent increase = [($587.40 / $549.45) - 1] x 100 = 6.91%

aliina [53]2 years ago
6 0
Old
9.99×55
=549.45
New
10.68×55
=587.4

((10.68÷9.99)−1)×100
=6.9%
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6 points Emily’s family needs to rent a moving truck to move their belongings to a different house. The rental cost for Trucks-A
Alexxx [7]

Answer/Step-by-step explanation:

Equation to represent the daily rental cost for each type of truck can be written as follows:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Where, m = Emily's mileage

To determine the number of miles for which the truck cost the same amount, set both equations equal to each other and solve for m.

42 + 0.72m = 70 + 0.12m

Collect like terms

0.72m - 0.12m = 70 - 42

0.6m = 28

Divide both sides by 0.6

\frac{0.6m}{0.6} = \frac{28}{0.6}

m = 46.7

At approximately 47 miles, both trucks would cost the same amount.

Check:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Plug in the value of x = 47

= 42 + 0.72(47) = $75.84 ≈ $76

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Plug in the value of x = 47

= 70 + 0.12(47) = $75.64 ≈ $76

7 0
2 years ago
Evelyn has $524.96 in her checking account. She must maintain a $500 balance to avoid a fee. She wrote a check for $32.50 today.
barxatty [35]

Answer:

524.96 − 32.50 + x ≥ 500

Amount need to deposit = $7.54

Step-by-step explanation:

Given:

Amount in checking account = $524.96

Maintain amount = $500

Amount of check = $32.50

Find:

Amount need to deposit

Computation:

Assume, amount need to deposit = x

So,

For avoiding fee

524.96 − 32.50 + x ≥ 500

x = 7.54

Amount need to deposit = $7.54

4 0
2 years ago
8. Peter and his partner are conducting a physics experiment on pendulum motion. Their 30-cm
katrin2010 [14]

Answer: 90/pi degrees

Step-by-step explanation:

It forms a 15cm arc from a circle of radius 30 cm.

The diameter is 30*2*pi = 60pi cm. So the arc is 15/60pi = 1/4pi of the way around a 360 degree circle. This is 1/4pi * 360 = 90/pi degrees.

Hope that helped,

-sirswagger21

8 0
2 years ago
Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy
motikmotik

Answer:

Hello your question is incomplete attached below is the complete question

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

Step-by-step explanation:

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

attached below is the detailed solution

4 0
2 years ago
Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1
astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

x^{2} - 24 = 1

Given that resulting expression is a second order polynomial of the form x^{2} - a^{2}, there are two real and distinct solutions. Roots of the expression are:

x_{1} = -5 and x_{2} = 5.

Now, it is also required to determine which part of the interval (x_{1}, x_{2}) is equal to a number greater than zero (positive). That is:

x^{2} - 24 > 0

x^{2} > 24

x < -4.899 and x > 4.899.

Therefore, exists two sub-intervals: [-5, -4.899] and \left[4.899,5\right]. Besides, x^{2} - 24 > y = 1 in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx

A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx

A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}

A = 2.525 -2.474+9.798 + 2.525 - 2.474

A = 9.9\,units^{2}

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

4 0
2 years ago
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