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Anna71 [15]
2 years ago
8

Line SU bisects angle RST. Which statement is NOT true?

Mathematics
2 answers:
bearhunter [10]2 years ago
8 0

Answer : The incorrect option is, (A) ∠RST = ∠RSU

Step-by-step explanation :

As we are given that, line SU bisects angle RST and SPUQ is a rhombus.

First we have to determine that ΔSQU and ΔSPU are congruent triangles.

Proof:

Side SU = Side SU (common side)

∠SQU = ∠SPU (In rhombus opposite angle are always equal)

∠RSU = ∠UST (angle bisector)

ΔSQU ≅ ΔSPU (By ASA congruency)

So, Side PS = Side QS

∠RST = ∠RSU this option is wrong because \angle RSU=\frac{1}{2}\angle RST

Thus, the incorrect option is, (A) ∠RST = ∠RSU

Lorico [155]2 years ago
5 0
In geometry, the angle bisector<span> theorem is concerned with the relative lengths of the two segments that a triangle's side is divided into by a line that bisects the opposite </span>angle<span>. It equates their relative lengths to the relative lengths of the other two sides of the triangle.
so the answer is B</span>
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The product of a number and 3 more than twice the number is 275. Find the number.
Gnom [1K]

Answer:

55

Step-by-step explanation:

if you do 3 times a number, 3x and twice more, 2x , that would be 5x divided by 275 which would be 55.

5 0
2 years ago
Sails come in many shapes and sizes. The sail on the right is a triangle. Is it a right triangle? Explain your reasoning.
Rudiy27

Answer:

not a right triangle

Step-by-step explanation:

you can use the pythagorean theorem to prove whether not this is a right triangle

if this triangle is a right triangle then the following equality should be true

a²+b²=c²

(9.75)²+(3.45)²=(10.24)²

(95.06)+(11.90)=(104.86)

106.96≠104.86

since the following equality is not true, this is not a right triangle.

3 0
1 year ago
Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

 

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

6 0
2 years ago
Read 2 more answers
How do I solve w(x)=4x 5; find w(-8)?
Andrei [34K]
Plug -8 in for x: 4(-8) + 5 solve: -32 + 5 -27
4 0
2 years ago
A forest ranger is in a forest 2 miles from a straight road. A car is located c miles down the road. The forest ranger can walk
Tcecarenko [31]

Answer:

  • T(x) = (√(4+x^2))/2 +(c -x)/4
  • (a) x = 1.155 miles
  • (b) x = 1/2 mile

Step-by-step explanation:

The straight line distance from the starting point to the point x on the road is given by the Pythagorean theorem:

  d1 = √(2²+x²)

The time required to walk that distance in the woods (at 2 miles per hour) is ...

  time = distance / speed

  t1 = √(4+x²)/2

The remaining distance along the road to the car is ...

  d2 = c - x . . . . . for c > x

and the corresponding time at 4 mph is ...

  t2 = (c -x)/4

Then the total time is ...

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(a) The value of x that minimizes total time is the one that makes the derivative zero.

  T'(x) = x/(2√(4+x²)) -1/4

  0 = (2x -√(4+x²))/(4√(4+x²))

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  4 +x² = 4x² . . . . . . square both sides

  4/3 = x² . . . . . . . . . subtract x², divide by 3

  x = (2/3)√3 ≈ 1.1547

If c = 9 miles, x = 1.1547 miles.

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(b) For c < (2/3)√3, the shortest travel time will be along the straight-line path to the car.

If c = 1/2 mile, x = 1/2 mile.

8 0
2 years ago
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