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1 year ago

Line SU bisects angle RST. Which statement is NOT true?

Mathematics

2 answers:

bearhunter [10]1 year ago

8 0

Answer : The incorrect option is, (A) ∠RST = ∠RSU

Step-by-step explanation :

As we are given that, line SU bisects angle RST and SPUQ is a rhombus.

First we have to determine that ΔSQU and ΔSPU are congruent triangles.

Proof:

Side SU = Side SU (common side)

∠SQU = ∠SPU (In rhombus opposite angle are always equal)

∠RSU = ∠UST (angle bisector)

ΔSQU ≅ ΔSPU (By ASA congruency)

So, Side PS = Side QS

∠RST = ∠RSU this option is wrong because $\angle RSU=\frac{1}{2}\angle RST$

Thus, the incorrect option is, (A) ∠RST = ∠RSU

Lorico [155]1 year ago

5 0

In geometry, the angle bisector theorem is concerned with the relative lengths of the two segments that a triangle's side is divided into by a line that bisects the opposite angle. It equates their relative lengths to the relative lengths of the other two sides of the triangle.
so the answer is B

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Find all of the polar coordinates of point P if p=(1,-pi/6)

Mama L [17]

Answer:

The all polar coordinates of point P are (1 , -pi/6 + 2nn) and (-1, -pi/6+(2n+1)n).

Step-by-step explanation:

The polar coordinates can be written as (r,Ф)= (r,Ф+2nn) or (r,Ф) =(-r,Ф+(2n+1)n) and n is any integer value.

We are given p=(1,-pi/6)

P(r,Ф), then r = 1 and Ф = -pi/6

The polar coordinates will be

P(r,Ф)= (r,Ф+2nn) = (1 , -pi/6 + 2nn) and n is any positive integer and the value of r is positive.

P(r,Ф) =(-r,Ф+(2n+1)n) = (-1, -pi/6+(2n+1)n) and n is any positive integer and the value of r is negative.

The all polar coordinates of point P are (1 , -pi/6 + 2nn) and (-1, -pi/6+(2n+1)n)

6 0

2 years ago

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The following curve passes through (3,1). Use the local linearization of the curve to find the approximate value of y at x=2.8.

Artist 52 [7]

d/dx (2 x^2 y + y = 2x + 13) 4xy + 2x^2 y' + y' = 2 4xy + y'(2x^2 + 1) = 2 y' = (2- 4xy)/(2x^2 +1)

ow we can use this in a linear equation for a slope Ty = -5x/8 +5(3)/8 +8/8 = -5x/8 +(15+8)/8 = -5x/8 +23/8 this will gives us an approximation at x=2.8 now

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2 years ago

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What is the value of k such that x-5 is a factor of x3 – x2 + kx - 30?

Paraphin [41]

Answer:

k = - 14

Step-by-step explanation:

given that (x - 5) is a factor of the polynomial then x = 5 is a root and

x³ - x² + kx - 30 = 0 for x = 5, that is

5³ - 5² + 5k - 30 = 0

125 - 25 + 5k - 30 = 0

70 + 5k = 0 ( subtract 70 from both sides )

5k = - 70 ( divide both sides by 5 )

k = - 14

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2 years ago

Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)

const2013 [10]

Answer:

The coefficients are

11,-4 and 0

Step-by-step explanation:

We are given two algebraic expressions. We are subtracting the second from the first.

First one is

$4x^2y^3+2xy^2-2y$

Second expression is

$-7x^2y^3+6xy^2-2y$

The given expression

= $4x^2y^3+2xy^2-2y-(-7x^2y^3+6xy^2-2y)\\=4x^2y^3+2xy^2-2y+7x^2y^3-6xy^2+2y\\=11x^2y^3-4xy^2+0y$

The coefficients are

11,-4 and 0

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1 year ago

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jake makes 9 loaves of olive bread. he uses 30 grams of olives in each loaf.he started with 1 kilogram of olives.how many grams

8090 [49]

Considering that 1 kilogram is equal to 1000 grams and he made 9 loaves of bread using 30 grams each time, that equates to 270 grams of olives. 1000 - 270 = 730. Your answer is 730 grams of olives remain. Hope this helped.

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2 years ago