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nevsk [136]
2 years ago
14

Juan invest $3700 in a simple interest account at a rate of 4% for 15 years

Mathematics
1 answer:
OleMash [197]2 years ago
8 0

<em><u>Question:</u></em>

Juan Invest $3700 In A Simple Interest Account At A Rate Of 4% For 15 Years. How Much Money Will Be In The Account After 15 Years?

<em><u>Answer:</u></em>

There will be $ 5920 in account after 15 years

<em><u>Solution:</u></em>

<em><u>The simple interest is given by formula:</u></em>

S.I = \frac{p \times n \times r }{100}

Where,

p is the principal

n is number of years

r is rate of interest

From given,

p = 3700

r = 4 %

t = 15 years

Therefore,

S.I = \frac{3700 \times 4 \times 15 }{100}\\\\S.I = 37 \times 4 \times 15\\\\S.I = 2220

<em><u>How Much Money Will Be In The Account After 15 Years?</u></em>

Total money = principal + simple interest

Total money = 3700 + 2220

Total money = 5920

Thus there will be $ 5920 in account after 15 years

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Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a
lisov135 [29]
1 mile at 12 m/h is .2 m/min
1 mile at .2 m/min (1/.2) = 5 min So the first mile took 5 minutes
To find how fast the second mile was:
You know it was 1 mile and it took 10 minutes
1/10=.1 m/min which is 6 m/h
The average speed is 6+12/2=9 m/h

Hope that helps.  Feel free to ask any questions.
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2 years ago
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In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?
valina [46]
To solve this problem, we need to know that 
arc length = r &theta;  where &theta; is the central angle in radians.

We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, &theta;
Rearrange equation at the beginning,
&theta; = (arc length) / r = 4pi / 6 = 2pi /3

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8 0
2 years ago
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Alice purchased 4 1⁄2 kilograms of olive oil for $27. What is the price per kilogram?
vitfil [10]

Hi!

We will solve this using ratios, like this:

4 1/2 = 4,5 kg of olive oil for 27 $

1 kg of olive oil for x $

_____________________________

x = (27*1)/4,5

x = 27/4,5

x = 6 $ per kilogram

Hope this helps!

8 0
2 years ago
A dealer paid $10,000 for a boat at an auction. At the dealership, a salesperson sold the boat for 30% more than the auction pri
pickupchik [31]
<span>Given situation:
=> A deadler paid $10 000 for a boat at an auction.
=> At the dealership, a sales person sold the boat for 30% more than the auction price
=> 10 000 dollars + 30%
=> Then the salesperson received a commission of 25% of the difference between the auction price and the dealership price
=> 10 000 + 25%
Let’s find the solution
=> 10 000 x .30 = 3000
=> 10 000 + 3 000 = 13 000, he sell it for this price
=> then he received a commission
=> 13 000 – 3 000 = 10 000
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=> 2500 , his commission </span>



7 0
2 years ago
A hospital finds that 22% of its accounts are at least 1 month in arrears. A random sample of 425 accounts was taken. What is th
GenaCL600 [577]

Answer:

8.85% probability that fewer than 82 accounts in the sample were at least 1 month in arrears

Step-by-step explanation:

For each account, there are only two possible outcomes. Either they are at least 1 month in arrears, or they are not. The probability of an account being at least 1 month in arrears is independent from other accounts. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.22, n = 425

So

\mu = E(X) = np = 425*0.22 = 93.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{425*0.22*0.78} = 8.54

What is the probability that fewer than 82 accounts in the sample were at least 1 month in arrears

This probability is the pvalue of Z when X = 82. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 93.5}{8.54}

Z = -1.35

Z = -1.35 has a pvalue of 0.0885.

8.85% probability that fewer than 82 accounts in the sample were at least 1 month in arrears

8 0
2 years ago
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