Answer:
The amount that should be in the account after 15 years is $95,321.85
Step-by-step explanation:
According to the given data, we have the following:
monthly amount of $220=R
interest rate is fixed at 2.05%. We require the monthly ineterest rate, hence monthly interest rate= 2.05%/12=0.1708%=0.0017
t=15years×12=180 months
In order to calculate how much should be in the account after 15 years, we would have to use the following formula:
Ap=<u>R(1-(1+i)∧-t)</u>
i
Ap=<u>220(1-(1+0.0017)∧-180)</u>
0.0017
Ap=<u>162,04</u>
0.0017
Ap=$95,321.85
The amount that should be in the account after 15 years is $95,321.85
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Answer:12
Step-by-step explanation:
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
Answer:
Is an estimate of the average grams of salt used in 2012
Step-by-step explanation:
Let
x ---> the number of years since 2012
f(x) ---> is the total amount of salt ingested in grams
we have
This is a linear equation in slope intercept form
where
The slope is equal to
The y-intercept or initial value is equal to
The y-intercept is the value of the function f(x) when the value of x is equal to zero
In this context, the y-intercept is the average amount of grams of salt ingested in the year 2012
The exact value of the average amount of grams of salt ingested in the year 2012 is 3,554 grams (see the data in the table)
Compare the exact value with the y-intercept
therefore
3,548 grams Is an estimate of the average grams of salt used in 2012
