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2 years ago

Which of the following best describes the slope of the line below? PLSSS HELP

Mathematics

1 answer:

12345 [234]2 years ago

4 0

The slope is zero. Slope formula is Y=mx+b and since B is 1.5 and it is a straight line, Y=mx+1.5. What plus 1.5 is 1.5? 0. Hope this helps.

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the jellybean jar has a radius of 4.8 cm and a height of 11.8 cm. what would be a reasonable lower limit for the number of jelly

azamat

Answer:

$\large\boxed{\large\boxed{100}}$

Explanation:

This question comes with four answer choices:

10,000
100,000
100
1

You just need to find a rough estimate of the volume of the jar and the volume of one jelly bean. This is called magnitude order.

The <em>jellybean ja</em>r is cylindrical, Thus, its volume is $\pi \times radius^2\times height$

To find the order of magnitude, you just use the numbers rounded to one signficant figure: round π to 3, the radius to 5, cm, and the height to 10:

$Volume\approx 3cm\times (5cm)^2\times10cm=750cm^3\approx1,000cm^3$

The order of magnitude for the radius of a jellybean is 1 cm. And the order of magnitude of the volume of a sphere with a radius of 1 cm is the cube of the diameter (2cm):

$(2cm)^3=8cm^3\approx10cm^3$

Hence, a reasonable lower limit for the number of jellybeans in the jar is:

$1,000cm^3/10cm^3=100$

7 0

2 years ago

Randi and her sister made balloon animals and sold the for. $0.50 each at the school carnival. They made $48.00. If Randi made t

evablogger [386]

Answer:

Balloon made by Randi's sister $=32$

Balloon made by Randi $=64$

Step-by-step explanation:

Let Randi's sister made $x$ balloons.

Balloons made by Randi $=2\times x=2x$

total ballons $=x+2x=3x$

$1$ cast of $1$ ballon $=\$0.50$

Cost of $x$ balloons $=3x\times0.50=1.5x$

Given total money made $=\$48.0$

$1.5x=48\\\\x=\frac{48}{1.5}\\\\x=32$

ballon made by Randi's sister $=32$

Ballon made by Randi's = $2\times32=64$

5 0

2 years ago

A book has 89 pages, but the page numbers are printed incorrectly. Every third page number has been omitted, so that the pages a

Sphinxa [80]

Answer:

Step-by-step explanation:

There are only 30 pages but last page number is 89.

8 0

2 years ago

Sections of prefabricated fencing are each 4 1/3 feet long. how long are 6 1/2 sections placed end to end

zalisa [80]

we know that

$4\frac{1}{3}= \frac{(4*3+1)}{3} =\frac{13}{3}$

$6\frac{1}{2}= \frac{(6*2+1)}{2}=\frac{13}{2}$

To find how long are $6\frac{1}{2}$ sections placed end to end

Multiply the number of sections by the length of one section

$\frac{13}{2} *\frac{13}{3} =\frac{169}{6}\ ft$

$\frac{169}{6}\ ft =28\frac{1}{6}\ ft$

therefore

<u>the answer is</u>

$28\frac{1}{6} \ ft$

6 0

2 years ago

Read 2 more answers

James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo

Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is $y = 2 ^n$

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒ n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒ for n = 1 , y = 2 ..... (1)

Similarly, if the paper if folded TWICE ⇒ n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒ for n = 2 , y = 4 ..... (2)

⇒ $y = 2^2 = 2^n$

Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7

So, $y = 2^ n = 2^7 = 128$

⇒ There are total 128 equal parts.

Lastly, if the paper is folded ELEVEN times ⇒ n = 11

So, $y = 2^ n = 2^{11} = 2048$

⇒ There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is $y = 2 ^n$

8 0

3 years ago