Zucchini plants require 9 square feet around each plant.

Mathematics

1 answer:

MrRa [10]2 years ago

4 0

The area of square TUVW = 3×3 = 9 square units

1 square unit = 4 head lettuces
9 square units = 9×4 = 36 lettuces

Area of plot QRST = length × width = 12×6 = 72 square units

36 vegetables for every 9 square units
We have 72÷9 = 8 lots of 9 square units

Total vegetable = 8 × 36 = 288 vegetables

We can have 8 different vegetables, each type can have 36 vegetables

You might be interested in

Which equation can you use to solve in the figure shown?

Neporo4naja [7]

What’s the figure I couldn’t see anything here.

5 0

2 years ago

The 2000 U.S. Census reports the populations of Bozeman, Montana, as 27,509 and Butte, Montana, as 32,370. Since the 1990 census

Nitella [24]

If the increase is x% per year, the multiplier each year is 1+x (expressed as a decimal).

Bozeman = 27,509·1.0196^t
Butte = 32,370·0.9971^t
where t is the number of years after 1990.

3 0

2 years ago

Read 2 more answers

If a hurricane was headed your way, would you evacuate? The headline of a press release states, "Thirty-four Percent of People o

IgorC [24]

Answer:

The 98% confidence interval would be given by (0.326;0.354)

Step-by-step explanation:

1) Notation and definitions

$X=63$ number of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

$n=6138$ random sample taken

$\hat p=0.34$ estimated proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

$p$ true population proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

2) Confidence interval

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 98% of confidence, our significance level would be given by $\alpha=1-0.98=0.02$ and $\alpha/2 =0.01$ . And the critical value would be given by: