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dedylja [7]
2 years ago
10

At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special. There are 5 c

hoices of sandwich, 4 choices of salad, and 3 choices of soup. How many possible lunch special combinations can be ordered?
Mathematics
1 answer:
Tju [1.3M]2 years ago
3 0

Answer: 35

Step-by-step explanation:

Given : At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special.

The number of choices for sandwiches = 5

The number of choices for salad = 4

The number of choices for soup = 3

Now, the number of  possible lunch special combinations can be ordered will be :-

5\times4+5\times3=20+15=35

Hence, the number of  possible lunch special combinations can be ordered will be 35.

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Juan runs a company that makes pens. He notices that 1 out of every 9 pens are faulty. He uses a standard deck of cards to model
sergey [27]

Question:

Isabella pitches for her high school softball team. Of the 7 pitches she throws, 5 are strikes. She uses a standard deck of cards to model her pitches, with hearts, clubs, and spades representing strikes. Which statement about her model is true?

Answer:

B. Her model can be improved the most by removing the queens and kings of hearts, clubs, and spades.

Explanation:

I took the test and passed.

6 0
2 years ago
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Which statements about the graph of the function y = (StartFraction 1 Over 3 EndFraction) Superscript x are true?
WARRIOR [948]

the function is decreasing and the y intercept is (0,1)

6 0
2 years ago
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Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zarrin [17]

Correction:

Because F is not present in the statement, instead of working on​P(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

So

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0
2 years ago
Mila reads at a rate of 2 paragraphs per minute. After reading for 3 minutes, she had read a total of 6 paragraphs. This situati
stira [4]

Answer:

(3,6)

Step-by-step explanation:

Given that Mila reads at a rate of 2 paragraphs per minute. After reading for 3 minutes, she had read a total of 6 paragraphs.

This situation can be represented with a linear equation written in slope-intercept form,  as

y=2x

where 'x' represents the number of minutes and,

y represents the number of paragraphs.  

Since y intercept is 0 i.e. 0 paras in 0 minutes we have the equation as

y=2x

Since no of minutes or paragraphs cannot take negative values this line is defined only in the I quadrant where both x and y are positive

Out of the points given as follows:

(3,6) (2,3) (-3,6) or (-2,6) ,

we can remove last two since they have negative x which is impossible.

Consider  (3,6) (2,3)

Out of these only I point  (3,6) satisfies  y=2x and second point   (2,3) does not satisfy

y=2x

Hence answer is (3,6)






8 0
2 years ago
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If a linear system has four equations and seven variables, then it must have infinitely many solutions. True or False
Savatey [412]

Answer:

The statement is False.

Step-by-step explanation:

Consider the provided information.

If a linear system has four equations and seven variables, then it must have infinitely many solutions.

We need to determine the above statement is true or false.

The above statement is false, it could be inconsistent, and therefore have no solutions,

For example:

x_1+x_2+x_3+x_4 +x_5+x_6+x_7=0\\x_1+x_2+x_3 =1\\x_4 +x_5 =1\\x_6+ x_7=1

Hence, there is no solution.

7 0
2 years ago
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