Answer:
The annual difference in the cost between the two cars in gasoline plus monthly payment per month will be $856.67.
Step-by-step explanation:
Car option "A" gets 18 miles per gallon of gas (MPG) and has a monthly payment of $368.
Now, yearly 12000 miles will consume 
gallons of gas.
Now, if the gas costs $2.89 par gallons, then yearly fuel cost is $(666.67 × 2.89) = $1926.67
Hence, the yearly cost for option A will be $(1926.67 + 368 × 12) = $6342.67.
Now, car option "B" is a hybrid and gets 60 MPG with a monthly payment of $409.
Now, yearly 12000 miles will consume 
gallons of gas.
Now, if the gas costs $2.89 par gallons, then yearly fuel cost is $(200 × 2.89) = $578
Hence, the yearly cost for option B will be $(578 + 409 × 12) = $5486.
So, the annual difference in the cost between the two cars in gasoline plus a monthly payment per month will be $(6342.67 - 5486) = $856.67. (Answer)
We can solve this problem by using the distance formula. The distance formula is: 
We can now put in values and solve.
To solve this we are going to use the formula fro the force applied to a spring:
where
is the spring constant
is the extension
Since we know the
, we can replace that in our formula and solve for
:
where
is the acceleration
is the spring constant
is the extension
is the mass
We know for our problem that
,
, and
. So lets replace those values in our formula to find
:
We can conclude that the acceleration of the block when s=0.4m is
.
Answer:
Step-by-step explanation:
The formula for <u>exponential growth</u> is y = ab^x.
To write this equation, we know it has to start with 48 (which is the variable a). We need to add the rate of growth. This is 11/6 (which is variable b). But we also need to account for the "every 3.5 years" part, so divide the x as an exponent by 3.5.
N(t) = 48 * 11/6^(t/3.5)
This equation is easy to test, and it's a good idea to test it after you write it. For example, after 3.5 years we know that it should have 48*11/6 branches. Does our equation work? Yes.
the chance of a positive response for Program 2 given that the individual is from Los Angeles is 69.7.
so tell me if i helped
