Question

A home’s value increases at an average rate of 5.5% each year. The current value is $120,000. What function can be used to find the value of the home after x years? f(x) = 120,000(1.055x) f(x) = 120,000(0.055)x f(x) = 120,000(1.055)x f(x) = [(120,000)(1.055)]x

Answer 1

Answer:

$f(x)=120000 \times (1.055)^{x}$

Step-by-step explanation:

We are given that the present value for the home is $120,000 and the rate of interest is 5.5% i.e. 0.055.

We will use the following formula:

$f(x)=P \times (1+r)^{x}$

where $P$ is the present value, $r$ is the rate of interest and $x$ is the number of years.

Substituting the values in the above formula to get:

$f(x)=120000 \times (1+0.055)^{x}$

$f ( x ) = 120000 \times ( 1.055 ) ^ { x }$

Answer 2

Answer:

C

F(x) = 120000(1.055)x

Step-by-step explanation:

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