Ask question

Ask question

All categories

1 year ago

12

The post office charges forty- six cents for the first ounce shipped, and thirty-three for each additional ounce. How much does

it cost to ship a package which weighs 22 ounces

1 answer:

Marat540 [252]1 year ago

7 0

Answer:

300

Step-by-step explanation:

2 6

You might be interested in

Which ordered pairs are solutions to the inequality 2y−x≤−6 ?

Vinil7 [7]

Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0

1 year ago

Consider a single spin of the spinner.

alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0

1 year ago

Read 2 more answers

Levi bought 14 chicken wings for $22.40 how much would it cost for 12 wings

777dan777 [17]

Answer:

x =19.20

Step-by-step explanation:

We can use ratios to solve

14 wings 12 wings

------------- = ---------------

22.40 x

Using cross products

14x = 22.40 * 12

14x =268.8

Divide each side by 14

14x/14 = 268.8/14

x =19.20

8 0

1 year ago

Read 2 more answers

Choose the function whose graph is given by:

loris [4]

<h2>Answer:</h2>

$y=3sec\left(\frac{1}{2}x\right)$

<h2>Step-by-step explanation:</h2>

The graphs of $sec(x)$ can be obtained from the graph of the cosine function using the reciprocal identity, so:

$sec(x)=\frac{1}{cos(x)}$

But in this problem, the graph stands for the function:

$y=3sec\left(\frac{1}{2}x\right)$

Because the period is now 4π as indicated and for $x=0$ in the figure and this can be proven as follows:

$Period=\frac{2\pi}{\frac{1}{2}}=4\pi$

Also, $for \ x=1 \ then \ y=3$ as indicated in the figure and this can be proven as:

$y=3sec\left(\frac{1}{2}x\right) \\ \\ y=\frac{3}{cos(0.5x)} \\ \\ y=\frac{3}{cos(0.5(0))} \\ \\ y=\frac{3}{1}=3$

5 0

1 year ago

(y^3+6y+3) and (y^2-6y-6)

Naily [24]

The answer is most definitely b.

3 0

2 years ago

Read 2 more answers