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Ira Lisetskai [31]
2 years ago
8

Four different prime numbers, each less than 20, are multiplied together. What is greatest possible result?

Mathematics
1 answer:
valentinak56 [21]2 years ago
8 0

Answer:

46,189

Step-by-step explanation:

The prime numbers that are less than 20 are :

1,2,3,5,7,11,13,17,19

to get the greatest value, we multiply the four numbers with the largest values i.e

11 x 13 x 17 x 19 = 46,189

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Find the cube root of 19683 by prime factorization method. Show steps.
ANTONII [103]

Answer:

  • 27

Step-by-step explanation:

<u>Given number:</u>

  • 19683

<u>Prime factors of 19683:</u>

  • 19683 = 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 = 3^9

<u>Cube root:</u>

  • ∛19683 = ∛3^9 = 3^3 = 27
3 0
2 years ago
Read 2 more answers
At the rate of 4 pens for C cents, how many pens Can I buy for 40 cents?
umka21 [38]
I'm not sure but I think it would be 10 pens hope this helps.
6 0
2 years ago
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Each of three colored cups covers one of three objects. 1) The red cup is somewhere to the left of the white cup. 2) The coin is
yulyashka [42]

Answer:

Shell is under Red color cup

Step-by-step explanation:

We have 3 cups and 3 objects which they cover under them.

Taking into consideration (4) and (2) as they both describe the position related to bean

(4) Gray cup  →Bean (right)     (2) coin ← bean (left)  

that means coin can either under Gray cup or left to gray cup.

Now

(1) Red ← White (left)  (3) Shell → Gray  (right)

This means if we consider coin to be left of gray cup then we can't place shell to the left of gray cup as required in (3)

so coin will be under gray cup

on forming the Color of cups and the coin below them

C1             C2         C3

Red       Gray      White

 __           __          __

Shell        coin        Bean

So Shell is under Red color cup

6 0
2 years ago
Assuming no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales b
alexira [117]

Answer:

Step-by-step explanation:

Given that we assume  no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales budget, the Deal product manager wishes to achieve a product contribution margin of 35%.

Sales - variable cost = Fixed cost + profit

Here fixed cost = 3 million dollars

Sales - variable = contribution = 35%

35% should atleast meet the fixed cost

i.e. 35% = 3 million

100% = 8.57 million can be cost

Since fixed cost will not change and remain 3 million these 5,57 million can be given to material and labor costs

So material and labor cost should be limited upto 5.57 million increase.

3 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
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