
Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.
Answer:
The cost per meal not including the $5
Step-by-step explanation:
or whatever is says something like that
Answer:
Options A, B and E represent mutually exclusive events.
Step-by-step explanation:
Two events are mutually exclusive that can not happen at a same time.
Now let us look at our options and find which statements represent mutually exclusive events.
A. We can see that landing on an unshaded portion and landing on 2 are mutually exclusive events as unshaded portion contains 3 and 4 and 2 lies on shaded portion.
B. Landing on a shaded portion and landing on 3 is also mutually exclusive as 3 lies on unshaded portion.
C. Landing on a shaded portion and landing on an even number can happen at the same time as 2 is an even number and it lies on shaded portion.
D. Landing on an unshaded portion and landing on a number greater than 3 can happen at the same time as 4 in greater than 3 and it lies on unshaded portion.
E. Landing on a shaded portion and landing on an unshaded portion are mutually exclusive events as spinner can be either in shaded portion or in unshaded portion.
Therefore, Options A, B and E are our correct choices.
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Make an equation for each statement with x being catcher's mitts and y being outfielder's gloves.
x + 10y = 239.50 and x + 5y = 134.50
Multiply the second equation through by -1 giving -x - 5y = -134.50
Combine the equations vertically
x + 10y = 239.50
-x - 5y = -134.50
giving
5y = 105
y = 21
Now substitute for y:
x + 10(21) = 239.50
x + 210 = 239.50
x = 29.50
Thus, Catchers mitts $29.50 and outfielder's gloves are $21