All categories

2 years ago

One batch of walnut muffins use 1 1/3 cups of walnuts.How many cups of walnuts are needed to 3 3/4 batches of muffins

Mathematics

2 answers:

Sophie [7]2 years ago

7 0

Answer:

3 1/4

Step-by-step explanation:

Ede4ka [16]2 years ago

5 0

All you have to do is since one batch needs 1 1/3 cup of walnuts multiply 1 1/3 to 3 3/4 = 3 1/4 cups

You might be interested in

Jessie has a deck of 52 regular playing cards and a bag of six marbles. In the bag, there are two blue marbles, three green marb

denpristay [2]

Answer:

Im so sorry i dont know

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The Lunar New Year festival is a 15-day celebration. How many weeks is that? Find the decimal number of weeks that is the same a

vagabundo [1.1K]

Answer:

B. It's actually something like 2.142857143... but you know, the closest answer is 2.14.

7 0

2 years ago

Before the distribution of certain statistical software, every fourth compact disk (CD) is tested for accuracy. The testing proc

lilavasa [31]

Answer:

a) For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

$P(R) =\frac{1}{4} =0.25$

The failure probability for each program are given by:

$P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01$

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

$P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932$

So then the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

And if we use the fact that we have 4 possible test the true probability of interest would be:

$P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017$

b) $p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))$

And replacing we got:

$p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484$

c) From part a we now that the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

So then if we have 100 CDs the expected number of rejected Cd's are:

$100*0.068= 6.8 \approx 7$

Step-by-step explanation:

Part a

For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

$P(R) =\frac{1}{4} =0.25$

The failure probability for each program are given by:

$P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01$

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

$P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932$

So then the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

And if we use the fact that we have 4 possible test the true probability of interest would be:

$P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017$

Part b

For this case we want the probability that it failed program 2 or 3

So then we can find this probability like this:

$p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))$

And replacing we got:

$p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484$

Part c

From part a we now that the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

So then if we have 100 CDs the expected number of rejected Cd's are:

$100*0.068= 6.8 \approx 7$

3 0

2 years ago

Andre has a bowl of chocolates where 70% of them are milk chocolate and the remaining 30% are

mylen [45]

Answer:

4) 7.9%

Step-by-step explanation:

Given:

% of milk chocolate = 70%

% of white chocolate = 30%

Total number of chocolate = 20

Number of milk chocolate:

$\frac{70}{100} * 20 = 14$

Number of white chocolate:

$\frac{30}{100} * 20 = 6$

From the calculations, we now know there are 14 milk chocolates and 6 white chocolates.

2 white chocolates are picked at random without replacement.

Probability first chocolate picked was white: $\frac{6}{20} = 0.3$

Probability second chocolate picked was white: $\frac{5}{19} = 0.2632$

To find probability that both of them are white chocolates, multiply probability of the first and second.

0.3 * 0.2632 = 0.07896

≈ 0.079

Convert to percentage by multiplying by 100.

0.079 * 100 = 7.9%

The probability that they are both

white chocolate is 7.9%

4 0

2 years ago

Solve the following quadratic equations by extracting square roots.Answer the questions that follow.

Vikentia [17]

Answer:

1. x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

Taking square root on both sides

$\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\$

x=±4

2. t^2=81

Taking square root on both sides

$\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}$

t=±9

3. r^2-100=0

$r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}$

r=±10

4. x²-144=0

x²=144

Taking square root on both sides

$\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}$

x=±12

5. 2s²=50

$\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}$

s=±5 ..

4 0

2 years ago

Read 2 more answers