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kolezko [41]
2 years ago
10

Assuming no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales b

udget, the Deal product manager wishes to achieve a product contribution margin of 35%. Given their product currently is priced at $35.00, what would they need to limit the material and labor costs to?
Mathematics
1 answer:
alexira [117]2 years ago
3 0

Answer:

Step-by-step explanation:

Given that we assume  no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales budget, the Deal product manager wishes to achieve a product contribution margin of 35%.

Sales - variable cost = Fixed cost + profit

Here fixed cost = 3 million dollars

Sales - variable = contribution = 35%

35% should atleast meet the fixed cost

i.e. 35% = 3 million

100% = 8.57 million can be cost

Since fixed cost will not change and remain 3 million these 5,57 million can be given to material and labor costs

So material and labor cost should be limited upto 5.57 million increase.

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7. If W = 3Z, and Z is 30% of R, then W is what
dem82 [27]

Answer:

90%

Step-by-step explanation:

Let R = 100

Since, Z = 30% of R

Therefore, Z = 30% *100 = 30

Since, W = 3Z

Therefore, W = 3*30 = 90

Percentage of W of R

= \frac{Value \: of \: W}{Value \: of \: R} \times 100\\\\=\frac{90}{100} \times 100\\\\Percentage \:of \:W \:of \:R =90\%

7 0
2 years ago
Your new flashlight uses a parabolic mirror which can be modeled by the equation (x – 2)² = 5(y + 1), where x and y are measured
Ksju [112]
The given equation is
(x - 2)² = 5(y + 1).

The given equation for the parabola is in the standard form
(x - h)² = 4p(y - k)
where
h = 2
4p = 5,    so that  p = 5/4
k = -1

The vertex is at 
(h,k) or (2, -1)

The focus is located at
(h, k + p) or (2, -1 + 5/4) = (2, 1/4)

We should place the bulb at p = 5/4 from the vertex.

Answer: 1 1/4 or 1.25 cm
 

6 0
2 years ago
Read 2 more answers
Draw a diagram that shows 1/5 times 30 equals 6. Please include a diagram
kobusy [5.1K]
The diagram included should explain this.

4 0
2 years ago
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Exercise 6.12 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they canno
tensa zangetsu [6.8K]
<h2>Answer with explanation:</h2>

As per given , we have

\hat{p}=0.48   , n=331

Critical value for 90% Confidence interval : z_{\alpha/2}=1.645

a) Confidence interval :

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

0.48\pm (1.645)\sqrt{\dfrac{0.48(1-0.48)}{331}}\\\\\approx 0.48\pm0.02746\\\\=(0.48-0.02746,\ 0.48+0.02746)\\\\=(0.45254,\ 0.50746)

Hence, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot a ord it : (0.45254,\ 0.50746)

b) Margin of error : E=1.5%=0.015

Formula for sample size : n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

For p =0.48 , we  have

n=0.48(1-0.48)(\dfrac{1.645}{0.015})^2=3001.88373333\approx3002

Hence, the required sample size to survey = 3002

6 0
2 years ago
A very weak university is on and off probationary status with the accrediting agency. A different procedure is used in July and
tino4ka555 [31]

Answer:

0.3425 = 34.25% probability it will be off probation in February 2020

Step-by-step explanation:

We have these desired outcomes:

Off probation in July 2019, with 0.25 probability, then continuing off in January, with 1 - 0.08 = 0.92 probability.

Still in probation in July 2019, with 1 - 0.25 = 0.75 probability, then coming off in January, with 0.15 probability.

What is the probability it will be off probation in February 2020?

p = 0.25*0.92 + 0.75*0.15 = 0.3425

0.3425 = 34.25% probability it will be off probation in February 2020

6 0
2 years ago
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