Answer:
m∠QPM=43°
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠NPQ=m∠MPN+m∠MPQ
we have
m∠NPQ=(9x-25)°
m∠MPN=(4x+12)°
m∠MPQ=(3x-5)°
substitute the given values and solve for x
(9x-25)°=(4x+12)°+(3x-5)°
(9x-25)°=(7x+7)°
9x-7x=25+7
2x=32
x=16
Find the measure of angle QPM
Remember that
m∠QPM=m∠MPQ
m∠MPQ=(3x-5)°
substitute the value of x
m∠MPQ=(3(16)-5)=43°
therefore
m∠QPM=43°
1)volume of the pipeline
The pipeline is a cylinder, therefore;
Volume (cylinder)=πr²h
r=radius
h=height of the cylinder
diameter=6 in*(1 ft / 12 in)=0.5 ft
raius=diameter / 2=0.5 ft / 2=0.25 ft.
height=5280 ft
Volume (pipeline)=π(0.25 ft)²(5280 ft)=330π ft³≈1036.73 ft³.
2) we calculate the number of barrel
1 mile of oil in this pipeline is 330π ft³ of oil.
1 barrel of crude------------------5.61 ft³
x----------------------------------330π ft³
x=(1 barrel*330π ft³) / 5.61 ft³=184.8 barrels
3) we calculate the price.
1 barrel---------------$100
184.8 barrels---------- x
x=(184.8 barrels * $100) / 1 barrel=$18,480
Solution: ≈$18,480
You substitute M for 3 and C for 6. So you get E = (3)(6)(2) which equals 36.
Answer:
It has a slope of zero because the change in the y-values is 0.
Step-by-step explanation:
