Hi. Please I need help with this :
1 answer:
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Answer:
x =
Step-by-step explanation:
Since it will be easier, just set "ce" as one term. Let ce = y
You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other.
Do the opposite of PEMDAS.
First, subtract 4 from both sides:
y = 7x + 4
y (-4) = 7x + 4 (-4)
y - 4 = 7x
Next, Divide 7 from both sides:
(y - 4)/7 = (7x)/7
(y - 4)/7 = x
x = (y/7) - (4/7)
Your value of x is
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Answer:
A.) Acceleration = 4.6 m/s^2
B.) Average speed = 47 m/s
Step-by-step explanation:
A.) From the graph, at t = 10s,
Velocity V = 46 m/s
Acceleration a = (change in V)/ time t
a = (46 - 0)/10
a = 46/10 = 4.6 m/s^2
B.) If we estimate the speed at 5 seconds intervals, then we have
Average speed = (36 + 46 + 49 + 50 + 50 +50 + 50) ÷ 7
Average speed = 331/7 = 47.29 m/s
Average speed = 47 m/s
Answer: The ball hits the ground at 5 s
Step-by-step explanation:
The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:
(1)
Where models the height of the ball in meters and
the time.
Now, let's find the time when the ball Sara kicked hits the ground (this is when
):
(2)
Rearranging the equation:
(3)
Dividing both sides of the equation by :
(4)
This quadratic equation can be written in the form , and can be solved with the following formula:
(5)
Where:
Substituting the known values:
(6)
Solving we have the following result:
This means the ball hit the ground 5 seconds after it was kicked by Sara.