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ahrayia [7]
2 years ago
14

Explain how the commutative property of addition,the Associative property of addition and mental math can help you find 75.2+(57

.376+24.8). What is the sum
Mathematics
2 answers:
4vir4ik [10]2 years ago
7 0

Answer: The sum of 75.2+(57.376+24.8) is 157.376.

Explanation:

The commutative property of addition states that,

a+b=b+a

The associative property of addition states that,

a+(b+c)=(a+b)+a

The given expression is 75.2+(57.376+24.8).

First use commutative property of addition in the parenthesis.

75.2+(57.376+24.8)=75.2+(24.8+57.376)

Now use associative property of addition.

75.2+(24.8+57.376)=(75.2+24.8)+57.376

Now simplify the expression,

(75.2+24.8)+57.376=100+57.376

(75.2+24.8)+57.376=157.376

Therefore, the sum of 75.2+(57.376+24.8) is 157.376.

galina1969 [7]2 years ago
5 0

Answer:

157.376

Step-by-step explanation:

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answer A radio station located 120 miles due east of Collinsville has a listening radius of 100 miles. A straight road joins Col
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Answer:

168.7602 miles

Step-by-step explanation:

One way to solve this problem is by using an equation that describes the listening radius of the station, and another for the road, then the points where this two-equation intersect each other will represent when the driver starts and stops listening to the station, and the distance between the points is the miles that the driver will receive the signal.

The equation for the listening radius (the radio station is at (0,0)):

x^2+y^2=100^2

The equation for the road that past through the points (-120,0) and (80,100) (Collinsville and Harmony respectively):

m=\frac{y_2-y_1}{x_2-x_1} =\frac{100-0}{80-(-120)}=\frac{100}{200}=\frac{1}{2}

y-y_1=m(x-x_1)\\y-0=\frac{1}{2}(x-(-120))\\ y=\frac{1}{2}x+60

Substitutes the value of y in the equation of the circle:

x^2+(\frac{1}{2}x+60)^2=100^2\\x^2+\frac{1}{4} x^2+60x+3600=10000\\\frac{5}{4} x^2+60x+3600=10000\\\frac{5}{4} x^2+60x+3600-10000=0\\\frac{5}{4} x^2+60x-6400=0\\5 x^2+240x-25600=0\\x^2+48x-5120=0\\

The formula to solve second-degree equations:

x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac} }{2a} \\x_{1,2}=\frac{-48\pm\sqrt{48^2-4(1)(-5120)} }{2(1)}\\x_{1,2}=\frac{-48\pm\sqrt{2304+20480} }{2}\\x_{1,2}=\frac{-48\pm\sqrt{22784} }{2}\\x_{1,2}=\frac{-48\pm16\sqrt{89} }{2}\\x_{1,2}=-24\pm8\sqrt{89} \\x_1=-24+8\sqrt{89}\approx51.4718\\x_2=-24-8\sqrt{89}\approx-99.4718\\

Using the values in x to find the values in y:

y_1=\frac{1}{2}x_1+60\\y_1=\frac{1}{2}(-24+8\sqrt{89} )+60\\y_1=-12+4\sqrt{89}+60\\ y_1=48+4\sqrt{89}\approx85.7359

y_2=\frac{1}{2}x_2+60\\y_2=\frac{1}{2}(-24-8\sqrt{89} )+60\\y_1=-12-4\sqrt{89}+60\\ y_1=48-4\sqrt{89}\approx10.2641

The distance between the points (51.4718,85.7359) and (-99.4718,10.2641) :

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