The refrigerant can hold 1.92 ft³
Step-by-step explanation:
The formula to apply is that of volume
v=π *r²*h where v is volume, r is radius of cylindrical object and h is height of tubing
Finding volume of using outside diameter
v=π*7/16*7/16*12
v=49/64 *3/1 *3.14
v=7.22 ft³
Volume using inside diameter
v=π*r²*h
v=3.14*3/8*3/8*12
v=5.30 ft³
Volume the refrigerant can hold is;
7.22-5.30 = 1.92 ft³
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Volume of a cylindrical object:brainly.com/question/2665971
Keywords :conditioning,system,roll,copper tubing,refrigerant
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