Answer:
Option d. PQ = YZ
Step-by-step explanation:
<u><em>The question in English is</em></u>
Choose the most appropriate answer. The PQR triangle and the XYZ triangle are two congruent triangles. The angle P = the angle Y and PR = YX. Side pairs of the same length are ... a. PQ = XZ b. QR = YZ c. QR = XY d. PQ = YZ
we know that
If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent
Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement
so
we have that


so
Triangle PQR is congruent with Triangle YZX
That means
<em><u>Corresponding angles</u></em>



<u><em>Corresponding sides</em></u>

Answer:
Step-by-step explanation:
The equation that models the height of the ball in feet as a function of time is

Where
is the initial height,
is the initial velocity and t is the time in seconds.
We know that the initial height is:
The initial speed is:

So the equation is:

The ball hits the ground when when
So

We use the quadratic formula to solve the equation for t
For a quadratic equation of the form

The quadratic formula is:

In this case

Therefore

We take the positive solution.
Finally the ball takes 2.47 seconds to touch the ground
Answer:
The ribbon cost per foot $0.6 per foot
Step-by-step explanation:
Total number of ribbon used = (5.75 + 11.75) = 17.50 feet
17.50 feet of ribbon cost = $10.50
1 foot of ribbon cost = x
Cross Multiply
17.50 × x = 1 foot × $10.50
x = 1 foot × 10.50/17.50
x = $0.6
The ribbon cost per foot $0.6 per foot
If you would like to know what was the percent decrease in price, you can calculate this using the following steps:
x% of $299.99 is $180.55
x% * 299.99 = 180.55
x/100 * 299.99 = 180.55
x = 180.55 * 100 / 299.99
x = 60.19%
100% - 60.19% = 39.81%
The correct result would be 39.81%.
Answer:
22 m
Step-by-step explanation:
The distance traveled is ...
d = (1/2)at^2
where "a" is the magnitude of the acceleration.
d = (1/2)(11 m/s^2)(2 s)^2
d = 22 m
The car traveled 22 meters while braking.