The tension in the string balances out, and thus equals the centripetal force of the ball
T = mv^2/r
<span>
if it only takes half the time to finish one orbit it has to be moving at twice the original speed. </span>
<span>
And since v is squared T will increase by 4 </span>
<span>
T' = m(2v)^2/r </span>
<span>
T' = 4mv^/r = 4T </span>
<span>
T' = 24.0 N
I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
</span>
This is<span> not the exact, precise </span>definition<span> of a </span>limit. If you would like to see the more precise and mathematical definition<span> of a </span>limit<span> you should check out the The </span>Definition<span> of a </span>Limit<span> section at the end of this chapter. The </span>definition<span> given above </span>is<span> more of a “working” </span>definition<span>.</span>
Given the equation of the parabola

The vertex of this parabola is placed at point (4,3).
If the equation of the parabola is
then

The coordinates of the parabola focus are

Therefore, the focus is placed at point (4,3,75).
Answer: option D, 0.75 in. above the vertex
Answer:

Step-by-step explanation:
Start by noticing that the angle
is on the 4th quadrant (between
and
. Recall then that in this quadrant the functions tangent and cosine are positive, while the function sine is negative in value. This is important to remember given the fact that tangent of an angle is defined as the quotient of the sine function at that angle divided by the cosine of the same angle:

Now, let's use the information that the tangent of the angle in question equals "-1", and understand what that angle could be:

The particular special angle that satisfies this (the magnitude of sine and cosine the same) in the 4th quadrant, is the angle 
which renders for the cosine function the value
.
Now, since we are asked to find the value of the secant of this angle, we need to remember the expression for the secant function in terms of other trig functions: 
Therefore the value of the secant of this angle would be the reciprocal of the cosine of the angle, that is: 