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Vlada [557]
2 years ago
14

A sphere has a radius of 16 in. Which statements about the sphere are true? Check all that apply.

Mathematics
2 answers:
mr_godi [17]2 years ago
7 0

Answer:

The True statements are:

The sphere has a diameter of 32 in.

The radius’s length is one-half the length of the diameter.

The volume of the sphere is StartFraction 16,384 Over 3 EndFraction pi inches cubed.

Step-by-step explanation:

  • The sphere has a diameter of 8 in. False

      This is false because a radius is half of a diameter. Half of      the given diameter of 8 in is 4 in whereas the radius in the question is 16 in.

  • The volume of the sphere is StartFraction 2,048 Over 3 EndFraction pi inches cubed. False

        This is false because the volume of the sphere is 4πr³/3 = (16,384/3) π cubic inches.

  • The sphere has a diameter of 32 in. True

This is True because a radius is half of a diameter. Half of the given diameter of 32 in is 16 in and  the radius in the question is also 16 in.

  • The radius’s length is one-half the length of the diameter. True

This is True because a radius is half of a diameter

  • The volume of the sphere is StartFraction 16,384 Over 3 EndFraction pi inches cubed. True

This is True because the volume of the sphere is 4πr³/3 = (16,384/3) π cubic inches.

  • The diameter’s length is one-half the length of the radius. False

It is the radius’s length that is one-half the length of the diameter

Wewaii [24]2 years ago
6 0

Answer:

  • The sphere has a diameter of 32 in. CORRECT: the diameter of a sphere doubles its radio, so if the radio equals 16,the diameter measures the double, in this case, 32.
  • The radius' lenght is one half the length of the diameter. CORRECT: , by definition, the diameter is the maximum distance between two opposite points on the surface of the sphere, and its lenght equals twice the radius because the radius is the distance between the center of the sphere and any point of the frontier of the sphere (then, one colud imagine that the distance between two opposite points in a sphere can be united by two radius, or a diameter).
  • The volume (V) of a sphere can be calculated as \frac{4\pi r^3}{3}, where r is the radio. In this case, the volume of the sphere will be \frac{4\pi\times16^3}{3}=\frac{4\pi\times4096}{3}, which is also equal to \frac{16384\times\pi}{3}.

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since the triangles are similar

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Answer:

Step-by-step explanation:

Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,

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Or z = \frac{x-10}{6}

is N(0,1)

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After traveling for 4 hours and 1800 miles, an airplane begins a steady descent. When it begins descending, its altitude (height
andrey2020 [161]

Answer:

Part 1)  Descending Rate = -2,000 ft/min

Part 2)  Starting altitude value is 33,000 ft

Part 3)  The linear equation for the plane's altitude (y) as a function of time (x) is:  y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft

Part 4)  The information not used for the equation is that the plane was travelling for 4 hours to cover 1800 miles before starting the descent

Step-by-step explanation:

Part 1)

The rate at which the airplane descends is given by the difference between final and initial altitude (17,000 ft-33,000 ft) divided the elapsed time (8 minutes):

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Part 2)

When graphing the descent (that is the plane's altitude as a function of time), the starting value for the altitude should be 33,000 ft

Part 3)

We can build the equation of the plane's altitude as a function of time in slope y-intercept form y = m x + b

by noticing that the slope "m" stands for the rate of descent that we found in part 1), and then using the information that at time zero (when the plane starts its descent), its altitude is 33000 ft:

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with this information about the intercept "b", we can write the final expression for the plane's altitude as a function of time during its descent as:

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Part 4)

The information that was not used to write the descent equation was the initial details about how long the plane traveled (4 hours) and for 1800 miles.

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