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cupoosta [38]
2 years ago
12

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than

60,000 miles. The manufacturer tests 250 tires and finds the mean life for these tires to be 64,500 miles.What is the alternative hypothesis being tested in this example
Mathematics
1 answer:
aleksandrvk [35]2 years ago
4 0

Answer:

The alternative hypothesis being tested in this example is that the tire life is of more than 60,000 miles, that is:

H_1: \mu > 60,000

Step-by-step explanation:

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles.

At the null hypothesis, we test if the tire life is of at most 60,000 miles, that is:

H_0: \mu \leq 60,000

At the alternative hypothesis, we test if the tire life is of more than 60,000 miles, that is:

H_1: \mu > 60,000

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Answer:  a) 278382 oz

b) 43 oz

c) 64.1 oz

Step-by-step explanation:

a) 8 T. 1,398 lb. 14 oz. × 6

First we need to change it in 'oz'.

As we know that

1\ ton=32000\ oz\\\\1\ lb=16\ oz

so, it becomes,

8\times 32000+1398\times 16+14\ oz\\\\=278382\ oz

8 T. 1,398 lb. 14 oz. × 6 becomes

278382\times 6\\\\=1670292\ oz

b) 349 lb. 6 oz. ÷ 130

It becomes,

349\times 16+6\ oz\\\\=5590\ oz\\\\\text{ at last it becomes}\\\\=\frac{5590}{130}\\\\=43\ oz

c) 6 T. 294 lb. ÷ 3,071

First it becomes,

6\times 32000+294\times 16\ oz\\\\=196704\ oz

At last it becomes,

\frac{196704}{3071}\\\\=64.1\ oz

Hence, a) 278382 oz

b) 43 oz

c) 64.1 oz

6 0
2 years ago
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Hello,

a) | |PA|-π |>| |PB|-π | (see pic)

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