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inn [45]
2 years ago
5

y = x2 + 11x + 24 is equivalent to the graph of which equation? y = (x + 8)(x + 3) y = (x + 4)(x + 6) y = (x + 9)(x + 2) y = (x

+ 7)(x + 4)
Mathematics
1 answer:
Montano1993 [528]2 years ago
7 0

Answer:

First option: y=(x + 8)(x + 3)

Step-by-step explanation:

Given the quadratic equation y = x^2 + 11x + 24, you need to factor it.

To do this, you need to find two number that when you add them you get 11 and when you multply them you get 24. These numbers are: 8 and 3.

Therefore, knowing this, you can factor the quadratic equation:

y = x^2 + 11x + 24\\\\y=(x + 8)(x + 3)

Then, y = x^2 + 11x + 24 is equivalent to the graph of the equation y=(x + 8)(x + 3), which matches with the first option.

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Which of the x values are solutions to the inequality 4(2 – x) > –2x – 3(4x + 1)? Check all that apply.
steposvetlana [31]
4(2 - x) > -2x - 3(4x + 1)
8 - 4x > -2x - 12x - 3
-4x + 2x + 12x > -3 - 8
10x > -11
x > -11/10
x > -1.1

Therefore, x = 0 and x = 10 zre solutions to the inequality.
4 0
2 years ago
Read 2 more answers
Ella completed the following work to test the equivalence of two expressions.
MrRa [10]
Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

3f + 2.6 = 3.1 + 2.6 = 3 + 2.6 = 5.6

2f + 2.6 = 2.1 + 2.6 = 2 + 2.6 = 4.6

5.6 = 4.6

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

3f + 2.6 = 2f + 2.6

3f = 2f

3f - 2f = 0

f = 0

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
6 0
1 year ago
Read 2 more answers
An experiment on memory was performed, in which 16 subjects were randomly assigned to one of two groups, called "Sentences" or "
FromTheMoon [43]

Answer:

There is no significant difference between the averages.

Step-by-step explanation:

Let's call

\large X_{sentences} the mean of the “sentences” group

\large S_{sentences} the standard deviation of the “sentences” group

\large X_{intentional} the mean of the “intentional” group

\large S_{intentional} the standard deviation of the “intentional” group

Then, we can calculate by using the computer

\large X_{sentences}=28.75  

\large S_{sentences}=3.53553

\large X_{intentional}=31.625

\large S_{intentional}=1.40788

\large X_{sentences}-X_{intentional}=28.75-31.625=-2.875

The <em>standard error of the difference (of the means)</em> for a sample of size 8 is calculated with the formula

\large \sqrt{(S_{sentences})^2/8+(S_{intentional})^2/8}

So, the standard error of the difference is

\large \sqrt{(3.53553)^2/8+(1.40788)^2/8}=1.34546

<em>In order to see if there is a significant difference in the averages of the two groups, we compute the interval of confidence of  95% for the difference of the means corresponding to a level of significance of 0.05 (5%). </em>

<em>If this interval contains the zero, we can say there is no significant difference. </em>

<em>Since the sample size is small, we had better use the Student's t-distribution with 7 degrees of freedom (sample size-1), which is an approximation to the normal distribution N(0;1) for small samples. </em>

We get the \large t_{0.05} which is a value of t such that the area under the Student's t distribution  outside the interval \large [-t_{0.05}, +t_{0.05}] is less than 0.05.

That value can be obtained either by using a table or the computer and is found to be

\large t_{0.05}=2.365

Now we can compute our confidence interval

\large (X_{sentences}-X_{intentional}) \pm t_{0.05}*(standard \;error)=-2.875\pm 2.365*1.34546

and the confidence interval is

[-6.057, 0.307]

Since the interval does contain the zero, we can say there is no significant difference in these samples.

6 0
2 years ago
Three orders are placed at a pizza shop. two small pizzas, a liter of soda, and a salad cost $14; one small pizza, a liter of so
mojhsa [17]
To determine the cost of each item, we need to set up equations. From the problem statement, we have three unknowns so we need three equations. We set up equations as follows:

let x cost of small pizzas
     y cost of soda
     z cost of salad
 
two small pizzas, a liter of soda, and a salad cost $14
2x + y + z = 14

one small pizza, a liter of soda, and three salads cost $15

x + y + 3z = 15

three small pizzas, a liter of soda, and two salads cost $22
3x + y + 2z = 22

Solving for x, y and z, we will have:

x = $ 5
y = $ 1
z = $ 3
6 0
2 years ago
Find the difference. Express your answer in
Leokris [45]

Answer:

-4g-3

------------

g+2

Step-by-step explanation:

g+1                     5g+4

-------------  -   ------------------

g+2                     g+2

Since the denominators are the same, subtract the numerators

g+1 - (5g+4)

Distribute the negative sign

g+1 -5g-4

-4g-3

Put this back over the denominator

-4g-3

------------

g+2

6 0
2 years ago
Read 2 more answers
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